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3 years ago

A math class is having a discussion on how to determine if the expressions 4x-x+5 and 8-3x-3 are equivalent using

Mathematics

1 answer:

Mkey [24]3 years ago

6 0

Answer:

Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.

Step-by-step explanation:

Both expressions are linear expressions. It takes 2 points to define a line. If the lines defined by each expression go through the same two points, then the expressions are equivalent.

If the expressions have the same value for two different variable values, they are equivalent. (choice D)

_____

Additional comment

One more point is needed than the degree of the polynomial expression. That is, quadratic (degree 2) expressions will be equivalent if they go through the same 2+1 = 3 points.

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Rite an algebraic expression to represent "five plus the quotient of r and 14."

hichkok12 [17]

The answer is 3) 5+r/14

Let's go segment by segment:
"five plus" means addition, so we have 5 +

"the quotient of r and 14" is the division result, so sign / must be present: 14/r

Therefore "five plus the quotient of r and 14" is 5 + 14/r

4 0

3 years ago

If b/a=c/b=d/c=2/3, find the value of a:b:c:d

leva [86]

Answer:

the ratio would be 6.75:4.5:3:2

Step-by-step explanation:

replace d and c with

d=2 and c=3

Then using proportion multiplication, you will find that b is 4.5

now replace all b with 4.5.

Then again using proportion multiplication, you will get a is 6.75.

Plug in a, b, c, d in the ratio and you get 6.75:4.5:3:2

5 0

2 years ago

Name a pair of whole number factors whose product is 8

hjlf

"Factors" just means numbers in the context of multiplication - so we just need to name a pair of numbers that, when multiplied, give 8.

Those would be: 1 and 8

2 and 4

so there are two solution to this question: 1 and 8, 2 and 4!

we can also include negative numbers:

-1 and -8
-2 and -4

because a multiplication of two negative numbers gives a positive result!

8 0

4 years ago

Tell whether the ordered pair is a solution to the equation. (1, 3); 4x – 3y = -5

Bumek [7]

Answer:

Yes

Step-by-step explanation:

4(1)-3(3)=-5

4-9=-5

-5=-5

8 0

2 years ago

Help help I don’t really get this???

insens350 [35]

Answer:

Question 4: $y=\displaystyle -\frac{4}{5}x$

Question 5: $y=-5x-3$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope of the line and b is the y-intercept (the y-coordinate of the point where the line crosses the y-axis).

Question 4

1) Determine the slope (m)

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$ where two points that pass through the line are $(x_1,y_1)$ and $(x_2,y_2)$

In the graph, two easy-to-identify points on the line are (-5,4) and (5,-4). Plug these into the equation:

$\displaystyle m=\frac{-4-4}{5-(-5)}\\\\\displaystyle m=\frac{-4-4}{5+5}\\\\\displaystyle m=\frac{-8}{10}\\\\\displaystyle m=-\frac{4}{5}$

Therefore, the slope of the line is $\displaystyle -\frac{4}{5}$ . Plug this into $y=mx+b$ as the slope (m):

$y=\displaystyle -\frac{4}{5}x+b$

2) Determine the y-intercept (b)

On the graph, we can see that the line crosses the y-axis when y is 0. Therefore, the y-intercept (b) is 0. Plug this into $y=\displaystyle -\frac{4}{5}x+b$ :

$y=\displaystyle -\frac{4}{5}x+0\\\\y=\displaystyle -\frac{4}{5}x$

Question 5

1) Determine the slope (m)

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Two easy-to-identify points are (-1,2) and (0,-3). Plug these into the equation:

$\displaystyle m=\frac{-3-2}{0-(-1)}\\\\\displaystyle m=\frac{-3-2}{0+1}\\\\\displaystyle m=\frac{-5}{1}\\\\m=-5$

Therefore, the slope is -5. Plug this into $y=mx+b$ :

$y=-5x+b$

2) Determine the y-intercept (b)

On the graph, we can see that the line crosses the y-axis at the point (0,-3). The y-coordinate of this point is -3. Therefore, the y-intercept (b) is -3. Plug this into $y=-5x+b$ :

$y=-5x+(-3)\\y=-5x-3$

I hope this helps!

8 0

3 years ago