The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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68,76 rounded to the nearest whole number will be equal 69
hope this will help you
Answer:
20%=8
10%=?
by cross multiplications,
10×8=80
80÷20=4
Hence the answer is 4.
The joint relative frequency values are the top-left four squares, or the intersection of 2 variables, divided by the total number in the bottom-right corner, which is 96.
Find the intersection of Camp and Swimming lessons. The number is 42. Divide this number by 96:
42 ÷ 96 = 43.75%
Best answer is 44%
The ground, the building and the line of sight between the ground camera and the top of the building form right triangle with hypotenuse equal to 45 feet and angle adjacent to this hypotenuse and ground - 50°. The building is an opposite leg to the given angle, then you should write sine function:
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The answer to the nearest tenth of a foot is 34.5 feet
