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Inessa05 [86]
3 years ago
5

A snail travels 9 inches in a span of 3 hours. Which of the following represents the rate of change the snail traveled with resp

ect to the time?
Mathematics
2 answers:
Misha Larkins [42]3 years ago
8 0
Oh I believe that Is 9/3=3
liq [111]3 years ago
4 0
This would become 9/3, and when simplified it becomes 3. Pls give brainliest
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A cylinder has a radius of 4x + 2 and a height of 5x + 4. Which polynomial in standard form best describes the total volume of t
forsale [732]
V = π r² h
V= π (4x+2)² (5x+4)
V = π (4x+2)(4x+2)(5x+4)
V = π (16x²+16x+4)(5x+4)
V= π(80x³+144x²+84x+16)
V= 251.33x³ +452.39x²+263.89x+50.27
4 0
3 years ago
3+4 40+3 30+4 which of these is another way to write
zhuklara [117]
(3+4) (40+3) (30+4) 
= 7 + 47 + 34
= (7+47) +35
=  54 + 35 
=   89
8 0
3 years ago
Read 2 more answers
PLEASE ANSWER THIS ONE!!!
Oliga [24]

Answer:

6:5

Step-by-step explanation:

i think this is it as I square rooted it and go that

7 0
3 years ago
Form the intersection for the following sets. E = {1, 2, 3} F = {101, 102, 103, 104} E ∩ F =
madam [21]
The intersection of two sets is a set that contains elements that are common to both sets.
There are no common elements in sets E and F, so the answer is the empty set.

<span>E ∩ F =  { }</span>
3 0
3 years ago
A helicopter is flying above a town. the local high school is directly to the east of the helicopter at a 20° angle of depressio
guapka [62]
Answer: 4.5 miles

Explanation:

When you draw the situation you find two triangles.

1) Triangle to the east of the helicopter

a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°

b) hypotensue = distance between the high school and the helicopter

c) opposite-leg to angle 20° = heigth of the helicopter

d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x

2) triangle to the west of the helicopter

a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°

b)  distance between the helicopter and the elementary school = hypotenuse

c) opposite-leg to angle 62° = height of the helicopter

d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x

3) tangent ratios

a) triangle with the helicpoter and the high school

tan 20° = Height / x ⇒ height = x tan 20°

b) triangle with the helicopter and the elementary school

tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°

c) equal the height from both triangles:

x tan 20° = (5 - x) tan 62°

x tan 20° = 5 tan 62° - x tan 62°

x tan 20° + x tan 62° = 5 tan 62°

x  (tan 20° + tan 62°) = 5 tan 62°

⇒ x = 5 tant 62° / ( tan 20° + tan 62°)

⇒ x = 4,19 miles

=> height = x tan 20° = 4,19 tan 20° = 1,525 miles

4) Calculate the hypotenuse of this triangle:

hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²

hipotenuse = 4.46 miles

Rounded to the nearest tenth = 4.5 miles

That is the distance between the helicopter and the high school.
5 0
3 years ago
Read 2 more answers
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