Answer:
A u = 0.36c B u = 0.961c
Explanation:
In special relativity the transformation of velocities is carried out using the Lorentz equations, if the movement in the x direction remains
u ’= (u-v) / (1- uv / c²)
Where u’ is the speed with respect to the mobile system, in this case the initial nucleus of uranium, u the speed with respect to the fixed system (the observer in the laboratory) and v the speed of the mobile system with respect to the laboratory
The data give is u ’= 0.43c and the initial core velocity v = 0.94c
Let's clear the speed with respect to the observer (u)
u’ (1- u v / c²) = u -v
u + u ’uv / c² = v - u’
u (1 + u ’v / c²) = v - u’
u = (v-u ’) / (1+ u’ v / c²)
Let's calculate
u = (0.94 c - 0.43c) / (1+ 0.43c 0.94 c / c²)
u = 0.51c / (1 + 0.4042)
u = 0.36c
We repeat the calculation for the other piece
In this case u ’= - 0.35c
We calculate
u = (0.94c + 0.35c) / (1 - 0.35c 0.94c / c²)
u = 1.29c / (1- 0.329)
u = 0.961c
Answer:
Total distance = 6.5 km
Explanation:
Let the distance be denoted by the vectors drawn from A, B, C, D, E, and F.
Then the distance covered can be calculated by adding the vectors in the direction given.
Total distance = 3km + 1km+ 1.5km+ 0.5km+ 0.5km
Total distance = 6.5 km
If we were to find the displacement ( shortest distance) then the head to tail rule would be applied using the vectors.
Answer:
B. 30m
Explanation:
This is because when a wave interferes constructively with another wave, they will add since constructive relates to joining or building up.
So, 10m + 20m equals a 30m wave.