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3 years ago

6

The ____ is a unique cabling system that allows one cable to be adapted to various services through the use of interchangeable m

odular connectors at both the work area outlet and the patch panel in the TR.

1 answer:

olganol [36]3 years ago

5 0

Answer:

ACO cable mate

Explanation:

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4 years ago

A metal rod has a length of 123. cm at 200°C. At what temperature will the length be 92.6 cm if the coefficient of linear expans

mestny [16]

Answer:

$\theta_{2} = 15400^0 C$

Explanation:

The formula for linear expansivity, $\alpha = \frac{l_{2} - l_{1} }{l_{1} ( \theta_{2} - \theta_{1} )}$

original length, l₁ = 123 cm = 1.23 m

final length, l₁ = 92.6 cm =0.926 m

original temperature, θ₁ = 200°C

Linear expansivity, α = 2 * 10⁻⁵ °C⁻¹

Putting these values into the formula:

$2 * 10^{-5} = \frac{1.23 - 0.926 }{l_{1} ( \theta_{2} -200 )}\\ \theta_{2} -200 = \frac{0.304}{2 * 10^{-5} } \\\theta_{2} = 15200 + 200\\\theta_{2} = 15400^0 C$

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3 years ago

the spring was compressed three times farther and then the block is released, the work done on the block by the spring as it acc

frosja888 [35]

Answer:

The work done on the block by the spring as it accelerates the block is 4kx².

Explanation:

Let initial distance is x.

It was compressed three times farther and then the block is released, new distance is 3x.

The work done in compressing the spring is given by :

$W=\dfrac{1}{2}k(x_2^2-x_1^2)$

$W=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\W=\dfrac{1}{2}k((3x)^2-x^2)\\\\W=\dfrac{1}{2}k((9x^2-x^2)\\\\W=\dfrac{1}{2}k\times 8x^2\\\\W=4kx^2$

So, the work done on the block by the spring as it accelerates the block is 4kx².

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3 years ago

Do metal atoms tend to gain or lose electrons?

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4 years ago

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