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NeX [460]
3 years ago
15

What is a disadvantage of shared decision-making?

Physics
1 answer:
Snezhnost [94]3 years ago
8 0
The disadvantages of shared decision making are:
Adopting a wrong advice from a member can lead to a big risk to the company and the business. 
Further, increased number of advice also confuses the person, about which to follow and which to ignore. 
There is also diffusion of responsibility and lowered efficiency.
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If a car has a velocity of 40 km/h west and then comes to a stop in 5 s, what is its acceleration in m/s2?
Leno4ka [110]

acceleration = change in velocity /change in time

convert 40km to meter then divide it with 5

6 0
3 years ago
Help help help HELP AAAAA
charle [14.2K]
The answer is B

As seen on the graph, the bus maintains a 9m/s speed for a majority of the trip to school.
5 0
3 years ago
if you dig a hole through the earth, from one hemisphere to the other, and drop a tennis ball into it, would it get stuck at the
tia_tia [17]

Answer:

Depending on which hemisphere it is, like western to eastern, It would most likely get stuck at the center. You would also have to put more things into thought like acceleration, velocity, and speed.

BUT since the question asked "would it pop out the other side?", I'm assuming it's talking about northern to southern hemisphere. so in that case it would pop out the other side since gravity makes things go downwards.

7 0
3 years ago
Read 2 more answers
Issac and Blaise decide to race. They both start at the same position at the same time. Issac runs at 2m/s but decides to take a
FromTheMoon [43]

Let the Blaise runs for time "t" to complete the race

so the total distance he moved is given by

d_1 = 1* t

Now Issac runs for time t = "t - 2*60"

because it took rest for 2 minutes

d_2 = 2*(t - 120)

now it is given that Blaise wins by 10 m distance

d_1 - d_2 = 10

1* t - 2*(t - 120) = 10

t - 2t + 240 = 10

t = 230 s

now the distance moved by Blaise is given by

d_1 = 1*230 = 230 m

6 0
3 years ago
A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds
Inessa05 [86]

Answer:

A body travels 10 meters during the first 5 seconds of its travel,and a total of 30 meters over the first 10 seconds of its travel

20miles / 5sec = 4miles /sec would be the average speed for the last 20 m

Explanation:

The answer is 4 m/s.

In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).

The relation of speed (v), distance (d), and time (t) can be expressed as:

v = d/t

We need to calculate the speed of the second 5 seconds of the travel:

d = 20 m (total 30 meters - first 10 meters)

t = 5 s (time from t = 5 seconds to t = 10 seconds)

Thus:

v = 20m / 5s = 4 m/s

PLEASE GIVE BRAINIEST!! HOPE THIS HELPS

5 0
3 years ago
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