If mass if a manis60kg.calculate his weight on earth and moon if the values of gram are 9.8 meter/second square and 1.6 meter/s
1 answer:
You might be interested in
Answer:
B) (-2.0 m, 0.0 m)
Explanation:
Given:
Mass of particle 1 is,
Mass of particle 2 is,
Position of center of mass is,
Position of particle 1 is,
Position of particle 2 is,
We know that, the x-coordinate of center of mass of two particles is given as:
Plug in the values given.
We know that, the y-coordinate of center of mass of two particles is given as:
Plug in the values given.
Therefore, the position of particle 2 of mass 3.0 kg is (-2.0 m, 0.0 m).
So, option (B) is correct.
Answer:
v = 14.32 m/s
Explanation:
According to the principle of conservation of linear momentum, both the momentum and kinetic energy of the system are conserved. Since the two balls are in the same direction of motion before collision, then;
+
= (
+
) v
0.035 × 12 + 0.120 × 15 = (0.035 + 0.120) v
0.420 + 1.800 = (0.155) v
2.22 = 0.155 v
⇒ v =
= 14.323
The velocity of the balls after collision is 14.32 m/s.