1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VashaNatasha [74]
3 years ago
5

If mass if a manis60kg.calculate his weight on earth and moon if the values of gram are 9.8 meter/second square and 1.6 meter/s

econd square in eathand moon's surface respectively.
Physics
1 answer:
katen-ka-za [31]3 years ago
6 0

Answer:

Explanation:

w = mg, and no matter where we go, our masses will never change. Our weight does, however, depending upon the gravity of where we are. Let's first find the weight of the man on earth, where the pull of gravity is -9.8 m/s/s:

w = (60)(-9.8) so

w = 590 N rounded from 588. It's negative because weight is a downward value (whereas Normal force is the upward value of this measurement, making Normal force the positive of this same number)

Now for the moon, where gravity is 1.6 m/s/s:

w = (60)(-1.6) so

w = -96 N

You might be interested in
Hey, I need help can someone help me out, please?
yan [13]

Explanation:

6) newton

7) f =ma = 15*15 = 225N

8) a= 100/20 = 5ms^-2

6 0
3 years ago
Read 2 more answers
A 0.400-kg object is swung in a circular path and in a vertical plane on a 0.500-m-length string. If the angular speed at the bo
Talja [164]

Answer:

T = 16.72 N

Explanation:

When the object is swung in a circular path, and in a vertical plane, there are two forces external to the object acting on it at any time: the gravity (which is always downward) and the tension in the string (which always points towards the center of the circle).

At the bottom of the circle, the tension is directly upward, so these two forces, are opposite each other, and the difference between them is the centripetal force , which at this point, keeps the object swinging in a circle.

This is the point of the trajectory where T is maximum.

We can apply Newton's 2nd Law, choosing an axis vertical (y-axis) being the upward direction the positive one, as follows:

T- m*g = m*a

The acceleration, at the bottom of the circle, is only normal (as there are no forces in the horizontal direction) , and is equal to the centripetal acceleration, as follows:

ac =  v² / r = ω²*r⇒ T- m*g = m*ω²*r

Replacing by the givens, we can solve for T as follows:

T = m* (ω²*r+g) = 0.4 kg*((8.00)² rad/sec²*0.5m)+9.8 m/s²) = 16.72 N

5 0
3 years ago
An object is dropped on Earth from a height of 15 m. What is the magnitude of the velocity of the object just as it hits the gro
ivolga24 [154]
Here, we know, according to 3rd Equation of Kinematics, 
v² - u² = 2as

Here, u = 0  [ Free fall ]
a = 9.8 m/s² [ constant value for the Earth system ]
s = 15 m

Substitute their values, 
v² - 0² = 2 * 9.8 * 15
v² = 294
v = √294
v = 17.15 m/s

In short, Your Answer would be Option D

Hope this helps!
8 0
3 years ago
Read 2 more answers
A 295-kg object and a 595-kg object are separated by 4.10 m.
kodGreya [7K]

Answer:

a)F=3 x 10⁻⁷ N

b)x=2.405 m

Explanation:

Given that

m₁=295 kg

m₂=595 kg

d= 4.1 m

a)

m₃=63 kg

r=d/2 = 2.05 m

The force between the mass m₁ and m₃

F_{13}=\dfrac{Gm_1m_3}{r^2}

by putting the values

F_{13}=\dfrac{Gm_1m_3}{r^2}

F_{13}=\dfrac{6.67\times 10^{-11}\times 295\times 63 }{2.05^2}

F₁₃=2.94 x 10⁻⁷ N

The force  between the mass m₂ and m₃

by putting the values

F_{23}=\dfrac{Gm_2m_3}{r^2}

F_{23}=\dfrac{6.67\times 10^{-11}\times 595\times 63 }{2.05^2}

F₂₃=5.94 x 10⁻⁷ N

The net force F

F= F₂₃- F₁₃

F=5.94 x 10⁻⁷ N-2.94 x 10⁻⁷ N

F=3 x 10⁻⁷ N

b)

Lest take at distance x from mass m₂ net force is zero.

F_{23}=\dfrac{Gm_2m_3}{x^2}

F_{13}=\dfrac{Gm_1m_3}{(4.1-x)^2}

Form above two equation

\dfrac{Gm_1m_3}{(4.1-x)^2}=\dfrac{Gm_2m_3}{x^2}

\dfrac{m_1}{(4.1-x)^2}=\dfrac{m_2}{x^2}

\dfrac{295}{(4.1-x)^2}=\dfrac{595}{x^2}

x²=2.01(4.1-x)²

x=1.42 (4.1-x)

x=5.82 - 1.42x

x=2.405 m

4 0
3 years ago
Compare skater's total energy at point A and at point E?(disregard the friction)
White raven [17]

Answer:

c

Explanation:

because I've had this question before and got it right

7 0
3 years ago
Other questions:
  • The 1994 Winter Olympics included the aerials competition in skiing. In this event skiers speed down a ramp that slopes sharply
    12·1 answer
  • These three members of the Nile gas family have one property in common because they are gases at room temperature. That is they
    5·1 answer
  • Use the following photoelectric graph to answer the following question:
    5·1 answer
  • An object is moving forward with a constant velocity. Which statement about this object MUST be true?
    8·1 answer
  • If two identical cars are traveling at different velocities, which car has the greatest momentum ​
    9·1 answer
  • When the distance between two masses is doubled, the gravitational attraction between
    10·1 answer
  • As blood passes through the capillary bed in an organ, the capillaries join to form venules (small veins). If the blood speed in
    11·1 answer
  • This will blow u r brains
    10·2 answers
  • A meteor moving 468 km per minute traveling in a south-to-north direction passed near Earth in 2013. Does this statement describ
    11·1 answer
  • Why do we "call it a day" when it's the end of the day/ night time?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!