It is a branch of mathematics that deals with the collection, organization presentation, analysis, and interpretation of data.
1. C. Discrete
2. A. interval
3. B. Quantitative data
4. B. Ratio
5. C. Quantitative
1. A random variable is called discrete if it has either a finite or a countable number of possible values.
A random variable is called continuous if its possible values contain a whole interval of numbers.
2. The third level of measurement is the interval level of measurement. The interval level of measurement not only classifies and orders the measurements but also specifies that the distances between each interval on the scale are equivalent along the scale from low interval to high interval.
3. Quantitative data consist of numerical measurements or counts.
4. Something measured on a ratio scale has the same properties that an interval scale has except, with a ratio scaling, there is an absolute zero point. Temperature measured in Kelvin is an example.
There is no value possible below 0 degrees Kelvin, it is absolute zero.
5. Qualitative data can be separated into different categories that are distinguished by some non-numeric characteristics.
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Is it together or different questions to the reading
Answer:
65.8 ft
Step-by-step explanation:
The number of strings required to tie each vertex to the other three will be ...
(4)(3)/2 = 6
Those strings will be perimeter strings plus two diagonal strings. The lengths of the perimeter strings are given as 12 ft and 7 ft. The lengths of the diagonal strings can be found using the Pythagorean theorem.
d² = 12² +7² = 144 +49 = 193
d = √193 ≈ 13.892
Then the total length of all strings is ...
L = 2(12.0 +7.0 +13.9) = 65.8 . . . . feet
The artist will need 65.8 feet of string.
First question seems incomplete :
Answer:
40 ways
Step-by-step explanation:
Question B:
Number of boys = 6
Number of girls = 4
Number of people in committee = 3
Number of ways of selecting committee with atleast 2 girls :
We either have :
(2 girls 1 boy) or (3girls 0 boy)
(4C2 * 6C1) + (4C3 * 6C0)
nCr = n! ÷ (n-r)!r!
4C2 = 4! ÷ 2!2! = 6
6C1 = 6! ÷ 5!1! = 6
4C3 = 4! ÷ 1!3! = 4
6C0 = 6! ÷ 6!0! = 1
(6 * 6) + (4 * 1)
36 + 4
= 40 ways
