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ANEK [815]
3 years ago
12

Distances in space are measured in light-years. The distance from Earth to a star is 6.8 × 1013 kilometers. What is the distance

, in light-years, from Earth to the star (1 light-year = 9.46 × 1012 kilometers)? (5 points)   2.66 light-years 7.18 light-years 7.74 light-years 9.46 light-years
Mathematics
2 answers:
baherus [9]3 years ago
8 0
I light year = 9.46 x 10¹² km

-------------------------------------------------------------------------------------
Find the number of light years
-------------------------------------------------------------------------------------

\text {Number of light years = } \dfrac{6.8 \times 10^{13}}{9.46 \times 10^{12}}

\text {Number of light years = } 7.18

-------------------------------------------------------------------------------------
Answer: The distance from Earth to the star is 7.18 light-years.
-------------------------------------------------------------------------------------

HACTEHA [7]3 years ago
6 0

Answer:

The distance from Earth to the star is 7.18 light-years


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gtnhenbr [62]

I'm guessing the sum is supposed to be

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\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}

1=a(5k+4)+b(5k-1)

If k=-\frac45, then

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If k=\frac15, then

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This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

S_n=\dfrac2{14}-\dfrac2{5n+4}

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\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17

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3 years ago
Which expression shows how 6 • 45 can be rewritten using the distributive property?
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marissa [1.9K]

Since the given hexagon is a regular hexagon all it's sides will be of equal length. Now, we know that the Area of any regular hexagon is given by:

A=\frac{3\sqrt{3}}{2} a^2

Where A is the area of the regular hexagon

a is the side length of the regular hexagon

Also, it's Perimeter is given by:

P=6a

Thus, all that we need to do is to find the side length of any one of the sides and to do that let us have a look at at the data of vertices points given and find out which points are definitely adjacent to each other and are also easy to calculate.

A quick search will yield that D(8, 0) and E(4, 0) are definitely adjacent to each other.

Please check the attached file here for a better understanding of the diagram of the original regular hexagon. Points D and E indeed are adjacent to each other.

Let us now find the distance between the points D and E using the distance formula which is as:

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

Where d is the distance.

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a_{small}=4-\frac{40}{100}\times 4=2.4

Thus, the area of the smaller hexagon will be:

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and the new smaller perimeter will be:

P_{small}=6a_{small}=6\times 2.4=14.4 unit

Which are the required answers.

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Klio2033 [76]

Answer:

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