Answer:
2. ![\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C0%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
3. ![\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%2621%2660%5C%5C-15%269%26-45%5C%5C%5Cend%7Barray%7D%5Cright%5D)
4. ![\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-14%5C%5C-2%26-6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
2. This matrix is easy, as it just requires addition.
+ ![\left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
3. This matrix requires for the matrices to be multiplied first, then added.
![\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-15%2618%5C%5C-27%2615%26-9%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-12%2636%2642%20%5C%5C12%26%20-6%20%26%20-36%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
4. Here we can add the last 2 matrices to find x.
![\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-8%5C%5C-4%262%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
Hope this helps! (Please consider giving brainliest)
Sin(2θ)+sin(<span>θ)=0
use double angle formula: sin(2</span>θ)=2sin(θ)cos(<span>θ).
=>
2sin(</span>θ)cos(θ)+sin(<span>θ)=0
factor out sin(</span><span>θ)
sin(</span>θ)(2cos(<span>θ)+1)=0
by the zero product property,
sin(</span>θ)=0 ...........(a) or
(2cos(<span>θ)+1)=0.....(b)
Solution to (a): </span>θ=k(π<span>)
solution to (b): </span>θ=(2k+1)(π)+/-(π<span>)/3
for k=integer
For [0,2</span>π<span>), this translates to:
{0, 2</span>π/3,π,4π/3}
It is true only whenever x tends to 0(zero)
it is not importent that x be in radian or in degree.
Answer:
Should be B
Step-by-step explanation:
3(6)+8=26
I think 26 is the answer
