3x + fraction 1 over 4 y^2 what is the value expression above when x=3 and y=4? Must show all work and calculations
1 answer:
Answer: 9 1/16
nine and one sixteenth
Step-by-step explanation:
Substitute x = 3 and y = 4 into the equation:
3x + 1/4^y
= 3(3) + 1/4^(2)
Then solve using the order BEDMAS (brackets, exponenets, division, multiplication, addition, subtraction).
= 3(3) + 1/4^(2)
= 3(3) + 1/16
= 9 + 1/16
= 9 1/16
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A = 180 - 143 = 37
b = 143
c = a = 37
e = a = 37
f = 90 - 37 = 53
d = 180 - 85 - 37 = 58
g = 48
h = 180 -48 -48 = 84
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