The anser is 6.25. Can you help me on mines?
Answer:
The normality requirement for a confidence interval estimate of sigma is (stricter) than the normality requirement for a confidence interval estimate of mu. Departures from normality have a (greater) effect on confidence interval estimates of sigma than on confidence interval estimates of mu. That is, a confidence interval estimate of sigma is (less)
Answer:
c
Step-by-step explanation:
Answer:
0.216
Step-by-step explanation:
![8 \times 1 \times 3 \times 0.1 \times 9 \times 0.01\\\\=(8\times1)(3\times0.1)(9\times0.01)\\\\=8(0.3)(0.09)\\\\=(8\times0.3)(0.09)\\\\=(2.4)(0.09)\\\\=2.4\times0.09\\\\=0.216](https://tex.z-dn.net/?f=8%20%5Ctimes%201%20%5Ctimes%203%20%5Ctimes%200.1%20%5Ctimes%209%20%5Ctimes%200.01%5C%5C%5C%5C%3D%288%5Ctimes1%29%283%5Ctimes0.1%29%289%5Ctimes0.01%29%5C%5C%5C%5C%3D8%280.3%29%280.09%29%5C%5C%5C%5C%3D%288%5Ctimes0.3%29%280.09%29%5C%5C%5C%5C%3D%282.4%29%280.09%29%5C%5C%5C%5C%3D2.4%5Ctimes0.09%5C%5C%5C%5C%3D0.216)
is this the standard form?
Answer:
-1 1/2
Step-by-step explanation:
-(3-6b)=6b + 5 .remember to balance!!!!
-6b + 6b= 6b + 6b
-3=12b+5
-3+5=5-5
-8=12b now divide since its the inverse operation
think 12/-8= -1 1/2
so B equals - 1 1/2