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Sloan [31]
4 years ago
8

ABC is translated 6 units up and 3 units left to create ∆A'B'C'.

Mathematics
1 answer:
aivan3 [116]4 years ago
6 0
B is the right answer for  this 

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If an object is dropped from a height of 200 feet, the function h(t)=-16t^2=200 gives the height of the object after t seconds.
Fed [463]
Hello,
Answer C
h(t)=0=-16t²+200==>t=3.53533...(s)
5 0
3 years ago
Which expression is equivalent to the following function?
nevsk [136]
<u>Answer </u>

B. f(x) = - (y/x)⁵

<u>Explanation</u>
A negative power means the reciprocal of that number raised to the positive value .
For example, a⁻ⁿ = 1/aⁿ

So, for the question above.
f(x) = -(x/y)⁻⁵
      = - 1/(x/y)⁵
      = - (y/x)⁵
6 0
3 years ago
Read 2 more answers
HELP ASAP GIVING BRAINLIEST!!! There are other questions, feel free to answer.
ozzi

Since we are asked to find the rate of change from Monday to Wednesday, we are dividing by 2, since Monday is day 1 and Wednesday is day 3. 3 - 1 = 2.

1800 + 500 = 2300 calories consumed Tuesday.

2300 - 100 = 2200 calories Wednesday.

(2200 - 1800)/2 = 400/2 = 200 calories  

4 0
2 years ago
Read 2 more answers
Three times the sum of a number 2 is the same as the number minus 4. Find the number.
Natali [406]

Answer:the number is ten

Step-by-step explanation:

5 0
4 years ago
A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum,  we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = \frac{x^{2} }{16}

For the equilateral triangle, the length of the side =  \frac{23 - x}{3}

Area = \frac{\sqrt{3} }{4}  a^{2}  = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}

Total Area = \frac{x^{2} }{16}  + \frac{\sqrt{3} }{36} (23-x)^{2}

\frac{dA}{dx}  = \frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x)\\

\frac{d^{2}A }{dx^{2} }  = \frac{1}{8}  + \frac{\sqrt{3} }{18}  > 0, therefore it is minimum

\frac{dA}{dx}  = 0 \\\\

\frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x) = 0\\

x = 10.00m

3 0
3 years ago
Read 2 more answers
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