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3 years ago

13

A car travels along a hill inclined 12º with the horizontal for a distance of 1200 feet. What is the horizontal distance travele

d by the car during this time?

1 answer:

ANTONII [103]3 years ago

7 0

Answer:

the horizontal distance traveled by the car during this time is 812

Step-by-step explanation:

You might be interested in

Median of 22, 16, 14, 26, 32, 30

n200080 [17]

Answer:

15

Step-by-step explanation:

cancel out from the sides till you have 1 number in the middle but in this case we have 2 numbers.

in a case like that you add both numbers and divide by 2 to get your answer

so 16+14÷2= 15

8 0

3 years ago

Read 2 more answers

You deposit $10,000 in an account that pays 4.5% interest compounded quarterly. Find the future value after one year.

Dominik [7]

Answer:

11800

Step-by-step explanation:

4.5%=0.045

0.045x10,000=450

450x4(quarterly)=1800

10,000+1800= 11800

5 0

3 years ago

Read 2 more answers

Plz hurry will mark brainliest

svetoff [14.1K]

Answer:

No they don't form a proportion

Step-by-step explanation:

Their denominatiors do not share a common multiple, therefore they can not form a proportion.

5 0

3 years ago

Find f(x)=x^2-x^3,find f(-10)

Elanso [62]

Answer:

Value of f(-10) is 1100

Step-by-step explanation:

Given that f(x) = x² - x³

Here we need to find f(-10).

f(-10) = (-10)² - (-10)³

f(-10) = 100 - (-1000)

f(-10) = 100 + 1000

f(-10) = 1100

Value of f(-10) is 1100

3 0

2 years ago

A hypothesis test is conducted at the .05 level of significance to test whether or not the population correlation is zero. If th

finlep [7]

Answer:

Th computed value of the test statistic is 3.597

Step-by-step explanation:

The null and the alternative hypothesis is as follows:

Null Hypothesis:

$\mathbf{H_o:}$ the population correlation coefficient is equal to zero

$\mathbf{H_a:}$ the population correlation coefficient is not equal to zero

The test statistics for Pearson correlation coefficient is thus computed as :

$t =\dfrac{r \sqrt{(n-2)}} { \sqrt{(1-(r)^2)} }$

where;

r = correlation coefficient = 0.60

n = sample size = 25

So;

$t =\dfrac{0.60 \sqrt{(25-2)}} { \sqrt{(1-(0.60)^2)} }$

$t =\dfrac{0.60 \sqrt{(23)}} { \sqrt{(1-0.36} }$

$t =\dfrac{0.60 *4.796} {0.8}$

t = 3.597

Comparing to a critical value of t (23 degrees of freedom two-tailed value) = 2.069

Decision Rule:

Since computed value of t is greater than the critical value of t; We reject the null hypothesis and accept the alternative hypothesis.

Conclusion:

We conclude that the population correlation coefficient significantly differs from 0 at 5% (0.05) level of significance.

6 0

3 years ago