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Arisa [49]
3 years ago
13

A car travels along a hill inclined 12º with the horizontal for a distance of 1200 feet. What is the horizontal distance travele

d by the car during this time?
Mathematics
1 answer:
ANTONII [103]3 years ago
7 0

Answer:

the horizontal distance traveled by the car during this time is 812

Step-by-step explanation:

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Solve the system of equations below by elimination.<br> (Show your work)<br> 2x+3y=1<br> 5x+7y=3
nikdorinn [45]

Answer:

-2x+2y+3z=0

-2x-y+z=-3

2x+3y+3z=5

---------------

-2x+2y+3z=0

-2x-y+z=-3

---------------- Subtract

3y + 2z = 3 Eqn A

=========================

-2x-y+z=-3

 

2x+3y+3z=5

---------------- Add

2y + 4z = 2

6y + 4z = 6 Eqn A times 2

------------------------------------ Subtract

-4y = -4

y = 1

-----------------

z = 0

-------------------

x = 1

8 0
3 years ago
Find the probability of having 2,3, or 4 successes in five trials of a binomial experiment in which the probability of success i
Georgia [21]

Answer:

65.3%

Step-by-step explanation:

Binomial distribution PMF below (along with a description)

the probabilty of getting 2, 3, or 4 successes in 5 trials is just

p(2)+p(3)+p(4)

p(2)= 5C2*.4²*(1-.4)³ = .3456

p(3)= 5C3*.4³*(1-.4)²= .2304

p(4)= 5C4*.4⁴*(1-.4)=.0768

.3456+.2304+.0768= .6528

6 0
2 years ago
What is the equation in point-slope form that represents the line going through (1,3) and (4,6)
Darya [45]
We have the slope m = (6-3)/(4-1) = 3/3 = 1;
Then, y - 3 = 1·( x - 1);
finally, y = x + 2.
3 0
3 years ago
Write a linear equation in standard form given the line passes through (-4,-3) and (6,-2).
garik1379 [7]
(-2+3)/(6+4)= 1/10

y+3=1/10(x + 4)

y + 3 = (1/10)x + 4/10

y + 30/10 = ( 1/10)x + 4/10

y = (1/10)x + 4/10 - 30/10

y = (1/10)x - 26/10

y = (1/10)x - 13/5

10(y = (1/10)x - 13/5)

10y = x - 26

-x + 10y = -26

7 0
3 years ago
2x+3y=19 // 6x+2y=22​
zvonat [6]

Answer:

(2, 5 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = 19 → (1)

6x + 2y = 22 → (2)

Multiplying (1) by - 3 and adding to (2) will eliminate the x- term

- 6x - 9y = - 57 → (3)

Add (2) and (3) term by term to eliminate x

0 - 7y = - 35

- 7y = - 35 ( divide both sides by - 7 )

y = 5

Substitute y = 5 into either of the 2 equations and solve for x

Substituting into (1)

2x + 3(5) = 19

2x + 15 = 19 ( subtract 15 from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

solution is (2, 5 )

7 0
3 years ago
Read 2 more answers
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