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hjlf
3 years ago
5

Could someone help me solve this

Mathematics
2 answers:
faltersainse [42]3 years ago
7 0

Answer:

x = 8.3.

Step-by-step explanation:

According to solve for the length of x, we need to use SOH CAH TOA.

This means...

Sine: Opposite over Hypotenuse

Cosine: Adjacent over Hypotenuse

Tangent: Opposite over Adjacent

In this case, we are given the angle, the hypotenuse, and we need to solve for the adjacent. This means that we will use cosine, since we have the adjacent and the hypotenuse.

cosine(41) = x / 11

x = (cosine(41)) * 11

x = 0.7547095802 * 11

x = 8.301805382

The question asks us to round to the nearest <em>tenth</em>.

So, your final answer is that x = 8.3.

Hope this helps!

sweet-ann [11.9K]3 years ago
4 0

Answer:

<h2>X=8.3</h2>

solution,

AC=11

BC=X

By trigonometry,

We know that

cos \: theta =  \frac{base}{hypotenuse}  =  \frac{bc}{ac}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \: cos \: 41 =  \frac{x}{11}  \\  \:  \:  \:  \:  \: x = 11 \: cos \: 41 \\  \:  \:  \:  \:  \:  x = 11 \times 0.754 \\  \:  \:  \:  \: x = 8.3

Hope this helps...

Good luck on your assignment...

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Calculate the gradient of the straight line which joins A(2,-3) and B(6,9)<br>​
Pie

Answer:

Gradient: m = 3

Step-by-step explanation:

m = change in y/change in x

m = \frac{Y2-Y1}{X2-X1}

m = \frac{9-(-3)}{6-(2)}

m = 12/4

m = 3

5 0
3 years ago
The rectangle shown represents the base of a cracker box shaped like a rectangular prism. Use the ruler provided to measure the
malfutka [58]

There is no rectangle shown, nor ruler given to measure and attempt your work. Nevertheless, I will illustrate how to find the volume of a rectangular prism.

Step-by-step explanation:

Given a rectangular prism of sides

Length = l

Width = w

Height = h

The volume of this prism is given as

V = l × b × h.

Example, if

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Width = 3cm

Height = 2cm

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7 0
2 years ago
Find the range of the following piecewise function.
Anna11 [10]

Given:

The piecewise function is

f(x)=\begin{cases}x+4 & \text{ if } -4\leq x

To find:

The range of given piecewise function.

Solution:

Range is the set of output values.

Both functions f(x)=x+4 and f(x)=2x-1 as linear functions.

Starting value of f(x)=x+4 is at x=-4 and end value is at x=3.

Starting value: f(-4)=-4+4=0

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Starting value of f(x)=2x-1 is at x=3 and end value is at x=6.

Starting value: f(3)=2(3)-1=5

End value: f(6)=2(6)-1=11

Least range value is 0 at x=-4 and 0 is included in the range because -4 is included in the domain.

Largest range value is 11 at x=6 and 11 is not included in the range because 6 is not included in the domain.

So, the range of the given piecewise function is [0,11).

Therefore, the correct option is A.

5 0
2 years ago
E is the midpoint of DF, DE = 2x + 4, and EF = 3x + 1. Find DE, EF, and DF.
Agata [3.3K]
When there is a midpoint in a line segment, the two segments that are then produced have to be equal. So that means that because E is a midpoint of DF, DE=EF.
Set up the equation.
DE=EF
2x+4=3x+1
Then solve for x.
x=3
Then plug it back in the equation to find DE and EF.
DE=2x+4=2(3)+4=10
Because DE=EF then EF is also 10.
DF is made from the addition of DE and EF so DF is twice EF.
DF= 20

DE= 10, EF= 10, DF= 20

Hope this helps.
8 0
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