Could someone help me solve this
2 answers:
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That trinomial can't be factored. You would have to complete the square to factor it and even then your answer would be an imaginary number.
x² + x + 12 = 0
x² + x = - 12
x² + x + 1/4 = - 12 + 1/4
x² + x + 1/4 = - 11 3/4
x² + x + 1/4 = - 47/4
(x + 1/2)² = - 47/4
x + 1/2 = +/- √(- 47/4)
x + 1/2 = +/-
x = 1/2 +/-
If the constant was a negative, it would be factor-able (is that a word?).
x² + x + 12 = 0
x² + x = - 12
x² + x + 1/4 = - 12 + 1/4
x² + x + 1/4 = - 11 3/4
x² + x + 1/4 = - 47/4
(x + 1/2)² = - 47/4
x + 1/2 = +/- √(- 47/4)
x + 1/2 = +/-
x = 1/2 +/-
If the constant was a negative, it would be factor-able (is that a word?).
Given: ∠ DEF
To construct: ∠TSZ ≅ ∠DEF
Construction: Consider the attachment
Step-01: Draw a line XY and choose a point S on it as a vertex of the required angle. Further marks point T such that DE = ST
Step-02: Take an arc AB from point E in ∠DEF of any length and draw at point S which cuts at point P on XY line.
Step-03: Take another arc of length AB from point B in ∠DEF and draw from point P which cuts to the previous arc at Q.
Step-04: Now, join the point SQ and extend up to Z such that EF = SZ
Hence, ∠ TSZ will be the required congruent constructed angle to∠DEF
