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Alex17521 [72]
3 years ago
12

A stadium has 50,000 seats. Seats sell for $35 in section A, $30 in section B, and $25 in section C. The number of seats in sect

ion A equals the total number of seats in section B and C. Suppose the stadium takes in $1,571,000 from each sold out event. How many seats does each section hold?
Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
The answer is Section A. has 25,000 seats,section B. has 12,500 seats and section C. has 12,500 seats.

How I got to the answer.
I divided 50,000÷4=12,500 then I multiplied 12,500×2=25,000.
I hope this helps.
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The answer is 3 and 2/5
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Imagine this like a fraction top:36+kt bottom: 36- 4kt. k=2. t=3
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6 0
3 years ago
10. A movie theater advertises that a family of two adults, one student, and one child between the ages of 3
BlackZzzverrR [31]

Answer:

Students ticket = $4

Child ticket = $1

Adult ticket = $5

Step-by-step explanation:

Let the price of the student ticket be $x and the price of a child ticket be $y.  An adult ticket costs as much as the combined cost of a student ticket and a child ticket, so the price of one adult ticket is $(x+y).

1. A movie theater advertises that a family of two adults, one student, and one child between the ages of 3 and 8 can attend a movie for $15. Then

2(x+y)+x+y=15

2. If you purchase 1 adult ticket, 4 student tickets, and 2 child tickets for $23, then

(x+y)+4x+2y=23

Now, solve the system of two equations:

\left\{\begin{array}{l}2(x+y)+x+y=15\\ \\(x+y)+4x+2y=23\end{array}\right.\Rightarrow \left\{\begin{array}{l}3(x+y)=15\\ \\5x+3y=23\end{array}\right.\\ \\\left\{\begin{array}{l}x+y=5\\ \\5x+3y=23\end{array}\right.\\ \\\left\{\begin{array}{l}y=5-x\\ \\5x+3(5-x)=23\end{array}\right.

Solve the last equation

5x+15-3x=23\\ \\2x=23-15\\ \\2x=8\\ \\x=4\\ \\y=5-x=5-4=1

Students ticket = $4

Child ticket = $1

Adult ticket = $5

8 0
3 years ago
Read 2 more answers
Cindy takes a sheet of paper and cuts from one corner to the opposite corner, making two triangles. If the piece of paper is 5 i
Westkost [7]

Answer:

Perimeter of one of the triangle= 17.071 inch

Step-by-step explanation:

The triangle has:

Perpendicular= 5 inch\\Base = 5 inch \\Diagonal(Hypotenuse)=?

Using the Pythagorean Theorem;

          ( Hypotenuse)^2=(Perpendicular)^2+(Base)^2\\H^2= 5^2+5^2\\H^2=25+25\\H^2=50\\

        H=\sqrt{50}\\or\\H=7.071 inches

The Perimeter of one of the triangle is =

                           Perpendicular+Base+Hypotenuse\\5+5+7.071\\17.071inch

This is equal for the other triangle.

6 0
3 years ago
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