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Alex17521 [72]
3 years ago
12

A stadium has 50,000 seats. Seats sell for $35 in section A, $30 in section B, and $25 in section C. The number of seats in sect

ion A equals the total number of seats in section B and C. Suppose the stadium takes in $1,571,000 from each sold out event. How many seats does each section hold?
Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
The answer is Section A. has 25,000 seats,section B. has 12,500 seats and section C. has 12,500 seats.

How I got to the answer.
I divided 50,000÷4=12,500 then I multiplied 12,500×2=25,000.
I hope this helps.
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Solve for the missing length and the other two angles in the triangle below
Klio2033 [76]

Answer:

AC = 3.72 units

Angles:

A = 132.6°

C = 27.4°

Step-by-step explanation:

AC² = 5² + 8² - 2(5)(8)cos(20)

AC² = 13.82459034

AC = 3.718143399

3.718143399/sin20 = 8/sinA

sinA = 0.7358944647

A = 180 - 47.38285134

A = 132.6171487

3.718143399/sin20 = 5/sinC

sinC = 0.4599340405

C = 27.38285134

5 0
3 years ago
Compute: 245 * 1,493. Show your work.
sesenic [268]
0 + 0 + 5 = 5

0 + 2 + 6 = 8

6 + 7 + 4 = 17
Put the 7 in the appropriate column and carry the 1.

<span>8 + 9 + 7 + </span><span>1(carried)</span><span> = 25</span>
Put the 5 in the appropriate column and carry the 2.

<span>9 + 5 + </span><span>2(carried)</span><span> = 16</span>
Put the 6 in the appropriate column and carry the 1.

<span>2 + </span><span>1(carried)</span><span> = 3</span>

<span>So: 1493 × 245 = 365785</span>
4 0
3 years ago
Find the equation of the line that is perpendicular to x - y = -5 and passes through (4, 7).
Ivanshal [37]
X - y = -5
-y = -x - 5
y = x + 5...slope here is 1. A perpendicular line will have a negative reciprocal slope. All that means is flip ur slope and change the sign. So our perpendicular line will have a slope of -1.

y = mx + b
slope(m) = -1
(4,7)...x = 4 and y = 7
now we sub and find b, the y int
7 = -1(4) + b
7 = -4 + b
7 + 4 = b
11 = b

so ur perpendicular equation is : y = -x + 11 <==
8 0
3 years ago
What are the solutions of x² + 6x - 16 = 0?
AveGali [126]

Step-by-step explanation:

x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}}{2\cdot \:1}\\\sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}\\\sqrt{6^2+64}\\\sqrt{36+64}\\\sqrt{100}\\\sqrt{10^2}\\=10\\x_1=\frac{-6+10}{2\cdot \:1},\:x_2=\frac{-6-10}{2\cdot \:1}\\\\\bold{x_1:2}\\\frac{-6+10}{2\cdot \:1}\\\frac{4}{2\cdot \:1}\\\frac{4}{2}\\=2\\\\\bold{x_2:-8}\\\frac{-6-10}{2\cdot \:1}\\\frac{-16}{2\cdot \:1}\\\frac{-16}{2}\\-\frac{16}{2}\\=-8

Answer:

x₁ = 2

x₂ = -8

6 0
1 year ago
A house cost $185,500 in 2000. By the year 2015, the value was $132,000. What was the growth rate as a percent for that 15-year
NemiM [27]
Wym their was no growth rate it lost 53,500 in those 15 years at a rate of about 3,566 a year
6 0
3 years ago
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