I need help with this please

Terrence took a total of 16 pages of notes during 8 hours of class. In all, how many hours will

r-ruslan [8.4K]

16 pages/8 hrs

2 pages/ he

18/2=9

18 pages/9 hrs

9 hours is your answer.

3 0

2 years ago

The number of guests per month at a large resort is given in the table below, where f(x) is the number of guests, in hundreds, x

Solnce55 [7]

X = 0 ; y = 10 ; 10 = a(0) + b(0) + c
c = 10

x=2 ; y = 15 ; 15 = a(4) + b(2) + 10 ; 5 = 4a+2b
x=4 ; y=18 ; 18 = a(16) + b(4) + 10 ; 8 = 16a + 4b

2(5) = (4a+2b)2
-
 8 = 16a + 4b
 2 = -8a

a = -0.25

b = 2

y = (1/4)x^2 + 2x + 10 ; 4y = x^2 + 8x + 40

8 0

3 years ago

Read 2 more answers

Please help me please

gizmo_the_mogwai [7]

Answer:

SA=390

Step-by-step explanation:

9*14=126

126+126=252

14*3=42

42+42=84

9*3=27

27+27=54

252+84+54=390

3 0

3 years ago

At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t

grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let X = temperature increase.

The random variable X follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of X is:

$f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.$

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

$P(X$

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

$P(20$

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

$P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467$

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable X as follows:

$E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5$

Thus, the expected value of the temperature increase is 17.5°C.

7 0

3 years ago

Please help Three fourths a number is less than six plus the number

fredd [130]

Answer:

3/4x < (x+6)

Step-by-step explanation:

4 0

3 years ago