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zavuch27 [327]
3 years ago
9

Which function below is growing the fastest?

Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0
They are growing at the same rate
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Easy points!!!
Softa [21]

Answer:

51, 52, 53

Step-by-step explanation:

51, 52, and 53 are all greater than 50, but less than 54

7 0
3 years ago
Consider the following simplified algebraic expression. Which could be the original expression?
dem82 [27]

You have to simplify each equation. You can do that by adding similar values to each other:

(the first equation)

8x²y + 7x² - 5y² + 3x - 2 + 2x²y - x² -  2y² + 3x - 4

To make it easier, arrange the values around so that similar ones are beside each other:

8x²y + 2x²y + 7x² - x² - 5y² - 2y² + 3x + 3x - 2 - 4

then add the similar values together:

8x²y + 2x²y = 10x²y

7x² - x² = 6x²

- 5y² - 2y² = -7y²

3x + 3x = 6x

(- 2)+ (- 4) = -6

and if you put them together:

10x²y + 6x² - 7y² + 6x - 6

This isn't the answer to the equation, because it's different. So repeat the process with all the other equations until you find one that is identical to the simplified version.

The answer is the second one: 8x²y + 7x² - 5y² + 3x - 2 + 2x²y - x² -  2y² - 3x - 4

6 0
3 years ago
Read 2 more answers
How would you solve 3x+6x+20=92
Radda [10]
3x + 6x + 20 = 92
9x + 20 = 92
9x = 72
x = 8
4 0
3 years ago
I have worked out trapezium's area but didn't work out triangle's. I need it fast, for tomorrow​
Soloha48 [4]

Answer:

<em><u>hope </u></em><em><u>this</u></em><em><u> answer</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> dear</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care</u></em><em><u> </u></em><em><u>and </u></em><em><u>may</u></em><em><u> u</u></em><em><u> have</u></em><em><u> a</u></em><em><u> great</u></em><em><u> day</u></em><em><u> ahead</u></em><em><u>!</u></em>

3 0
3 years ago
How would you write apples grow on trees in conditional statements?
MariettaO [177]
If it is an apple, then it grows on trees.
4 0
3 years ago
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