Answer:
negative correlation on Edg
Step-by-step explanation:
P ( work/ senior ) = 0.14
The attached table
required
P ( work/ senior )
This is calculated using:
P ( work/ senior ) = n ( work/ senior )/ n ( senior ).
n ( work/ senior ) = 5
n ( senior ) = 25 + 5 + = 35
So:
P ( work/ senior ) = 5/35
P ( work/ senior ) = 0.14
Add 25+5+5 (because that is all the numbers in the 'Seniors' row) and then take the 5 that is in the 'Work' column and put that over 25. (5/25 fraction as a percent is 14).
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A.) If Lucy sells 1 necklace, her sales would equal to $15.99. Then her profit would be:
Profit = $15.99 - $3.38(1) - $5.57(1)
Profit = $7.04
The fraction of the sale price of the necklace in profit is denoted as x.
15.99x = 7.04
x = 704/1559
b.) This is the same as part (a) but in decimal form. Just simply divide 704 by 1559. The answer is 0.44
c.) If Lucy's sales is $223.86 and each necklace costs $15.99, then the number of necklaces sold is $223.86 ÷ $15.99/necklace = 14 necklaces
Her profit for the 14 necklaces sold would be:
$223.86 - $3.38(14) - $5.57(14) = $98.56
Answer:
Hi your question is incomplete attached below is the complete question
answer : p ( X < 725 ) = 0.0116
Step-by-step explanation:
Given data:
Average life of bulbs (μ ) = 750 hours
standard deviation (б ) = 55 hours
n ( sample size ) = 25
X = 725
<u>Probability that the mean life of a random sample of 25 bulbs will be less than725 hours </u>
p ( X < 725 ) = p (( X - μ )/ б √n < 725 - 750 / 55√25 )
= P ( Z > - 2.27 )
Hence P ( X < 725 ) = 0.0116 ( using Z-table )
