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Stolb23 [73]
3 years ago
6

How many solutions does this system have? x-y=-4 3x+y=8 one two an infinite number no solution

Mathematics
1 answer:
tatuchka [14]3 years ago
3 0

Answer:

work is shown and pictured

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Let f(x)=16x^5-48x^4-8x^3 and g(x)= 8x^2. find f(x)/g(x)
Gekata [30.6K]

Answer:

2x³ - 6x² - x

Step-by-step explanation:

Divide each term in f(x) by g(x), that is

\frac{16x^5}{8x^2} - \frac{48x^4}{8x^2} - \frac{8x^3}{8x^2}

= 2x^{(5-2)} - 6x^{(4-2)} - x^{(3-2)}

= 2x³ - 6x² - x

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A student council collects aluminum pop tabs to raise money to purchase a wheelchair. A company buys the pop tabs for $0.88 per
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Answer:

$1500

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3 years ago
What is the least common multiple of 16 and 22?
hammer [34]

Answer:

the answer is 176 hope this helps

Step-by-step explanation:

4 0
4 years ago
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Select the values of that are solutions to the inequality x^2+3x-4>0
sergey [27]
Solution:x^2+3x-4=(x+4)(x-1)>0,
therefore, the x range is (-∞,-4)∪(1,+∞).
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3 years ago
The rabbit population on a small island is observed to be given by the function P(t) = 130t − 0.4t^4 + 1200 where t is the time
olya-2409 [2.1K]
A.) P(t) = 130t - 0.4t^4 + 1200
The population is maximum when P'(t) = 0
P'(t) = 130 - 1.6t^3 = 0
1.6t^3 = 130
t^3 = 81.25
t = ∛81.25 = 4.3 months.

Maximum population P(t)max = 130(4.3) - 0.4(4.3)^4 + 1200 = 1,622

b.) The rabbit population will disappear when P(t) = 0
P(t) = 130t - 0.4t^4 + 1200 = 0
 t ≈ 8.7 months
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3 years ago
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