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Taya2010 [7]
3 years ago
9

Given sinx=0.5 , what is cosx ?

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
7 0
The arc sine of 0.5 is 30 degrees Therefore x = 30 degrees
The cosine of x = cosine of 30 degrees = 0.86603
(rounded to nearest hundredth is .87)


Dafna1 [17]3 years ago
6 0

Answer:

The value of cosx is \pm0.87

Step-by-step explanation:

We have been given that \sin x= 0.5

We know the relation between sine and cosine

\sin^2x+\cos^2x=1

On solving the equation for cosx, we get

\cos x=\pm\sqrt{1-\sin^2x}

Plugging the value of sinx, we get

\cos x=\pm\sqrt{1-(0.5)^2}

On simplifying, we get

\cos x=\pm\sqrt{0.75}\\\\\cos x=\pm0.87

Therefore, the value of cosx is \pm0.87

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Prime factors of 20 i dont know this question
dem82 [27]

Answer:

 2 x 2 x 5,

Step-by-step explanation:

20 = 1 x 20

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Factors of 20= 1, 2, 4, 5, 10, 20.

Prime factors are = 2 x 2 x 5,

6 0
3 years ago
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The function f(t) = 33 sin (pi over 2t) − 20 models the temperature of a periodic chemical reaction where t represents time in h
Gennadij [26K]
The given function is
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Because the maximum and minimum values for the Sine function are +1 and -1 respectively,
The maximum value of f  = 33 - 20 = 13.
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The period, T,  is given by
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Answer:
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4 0
3 years ago
Drag the labels to the correct locations on the table. Each label can be used more than once.
Julli [10]

Answer:

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6 0
3 years ago
Round to the nearest tenth: 6.932635<br> 6.9<br> 6<br> 6.8<br> 7
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6.1.3
Nata [24]

Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

Step-by-step explanation:

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If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

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Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

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