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statuscvo [17]
2 years ago
10

Find the area of each figure.Round to the nearest tenth if necessary square 17.6mm

Mathematics
1 answer:
balandron [24]2 years ago
5 0

Answer:

309.8 mm² (nearest tenth)

Step-by-step explanation:

\boxed{area \: of \: square = side \times side}

Given that the side of the square is 17.6mm,

area of square

= 17.6 ×17.6

= 309.76

= 309.8 mm² (nearest tenth)

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A line passes through the point (-4, -2) and has a slope of -5/2. Write an equation in slope- intercept form for this line.
kirill115 [55]

Answer:

<h2>           y = -⁵/₂x - 12 </h2>

Step-by-step explanation:

The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:

m = -⁵/₂

(-4, -2)    ⇒   x₀ = -4,  y₀ = -2

The point-slope form of the equation:

y + 2 = -⁵/₂(x + 4)

So:

y + 2 = -⁵/₂x - 10         {subtract 2 from both sides}

y = -⁵/₂x - 12             ←  the slope-intercept form of the equation

5 0
2 years ago
Zander read 13 3/4pages in 1/4 of an hour. Sydney read 43 1/3 pages in 2/3 of an hour. At these rates, would Zander or Sydney re
kakasveta [241]

Answer:

At these rates Sydney read 10 pages per hour more than Zander.

Step-by-step explanation:

Zander read 13\frac{3}{4} pages in \frac{1}{4} of an hour.

Therefore, pages read by Zander in 1 hour = \frac{\text{Total pages read}}{\text{Total time taken}}

= \frac{13\frac{3}{4}}{\frac{1}{4}}

= \frac{55}{4}\times \frac{4}{1}

= 55 pages per hour

Sydney read 43\frac{1}{3} pages in \frac{2}{3} of an hours.

Pages read by Sydney in 1 hour = \frac{43\frac{1}{3}}{\frac{2}{3} }

= \frac{130}{3}\times \frac{3}{2}

= 65 pages per hour

Therefore, number of pages read more by Sydney as compared to Zander,

= 65 - 55

= 10 pages per hour

At these rates Sydney read 10 pages per hour more than Zander.

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2 years ago
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This lists the group of 6 sets.

30 red marbles in 6 sets.
8 0
3 years ago
2x + 5y = 9<br> The line perpendicular to the given line is?
ale4655 [162]

Answer:

Step-by-step explanation:

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