Ask question

Ask question

All categories

Ilia_Sergeevich [38]

3 years ago

11

A circle is drawn within a square as shown. What is the best approximation for the area of the shaded region? Use 3.14 to approx

imate pi. 10.54 cm² 27.02 cm² 87.47 cm² 104.86 cm²

1 answer:

shusha [124]3 years ago

5 0

You didn't add the picture with the measurements, but I saw this somewhere else so I know the answer is 10.54

You might be interested in

A rectangle has a length of x inches and a width 2 inches less than the length. If the dimensions were tripled what would be the

vagabundo [1.1K]

Originally we have
length = x
width = x-2
since the width is 2 inches smaller than the length

now let's triple each dimension. Multiply the expressions by 3 to get
new length = 3*x
new width = 3*(x-2) = 3x-6

Now onto the area
area = (length)*(width)
area = (3x)*(3x-6)
area = 3x*3x-3x*6
area = 9x^2 - 18x

So the new larger rectangle has area of 9x^2-18x

3 0

2 years ago

The equation 7^2=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A

jeyben [28]

Answer:

The period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

Step-by-step explanation:

The equation $T ^ 2 = a ^ 3$ shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?

For the planet Y:

$T_y ^ 2 = a_y ^ 3$

For planet X:

$T_x ^ 2 = a_x ^ 3$

To know the factor of aumeto we compared $T_x$ with $T_y$

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:

$a_y ^ 3 = (a_xk) ^ 3$

So

$\frac{T_y ^ 2}{T_x ^ 2}=\frac{a_y ^ 3}{a_x^ 3}\\\\\frac{T_y ^ 2}{T_x ^ 2}=\frac{(a_xk)^3}{a_x ^ 3}\\\\\frac{T_y^ 2}{T_x^ 2}=\frac{k ^ {3}a_{x}^ 3}{a_{x}^ 3}\\\\\frac{T_{y}^ 2}{T_{x}^ 2}=k ^ 3\\\\T_{y}^ 2 = T_{x}^{2}k^{3}\\\\T_{y} =k^{\frac{3}{2}}T_x$

Then, the period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

4 0

3 years ago

What is the difference between experimental and nonexperimental methods of study? Nonexperimental methods involve operational de

Anon25 [30]

Experimental methods involve the manipulation and control of variables, whereas non experimental methods require simple observation of the variables.

Answer: Option D.

<u>Explanation:</u>

Non-experimental research about doesn't mean nonscientific. Non-experimental investigate implies there is an indicator variable or gathering of subjects that can't be controlled by the experimenter. Test plan, then again, takes into consideration specialists to control the indicator variable and subjects.

Non experimental research falls into three broad categories: single-variable research, correlational and quasi-experimental research, and qualitative research.

3 0

3 years ago

Find the difference between 3 more than 1/3 and 3.

AveGali [126]

Answer:

1/3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The function f(x)= -1/4(x) +1 is getting closer to a particular number. Its initial values are 4 and -2, what happens to the val

Basile [38]

Answer:

After 10 iterations, the value is approximately the value it gets closer each time, which is 0.8 (or 4/5)

Step-by-step explanation:

If the inicial value is 4, we have:

1: f(4) = -1/4(4) + 1 = 0

2: f(0) = -1/4(0) + 1 = 1

3: f(1) = -1/4(1) + 1 = 3/4

4: f(3/4) = -1/4(3/4) + 1 = 13/16

5: f(13/16) = -1/4(13/16) + 1 = 51/64

6: f(51/64) = -1/4(51/64) + 1 = 205/256

7: f(205/256) = -1/4(205/256) + 1 = 819/1024

8: f(819/1024) = -1/4(819/1024) + 1 = 3277/4096

9: f(3277/4096) = -1/4(4) + 1 = 13107/16384

10: f(13107/16384) = -1/4(13107/16384) + 1 = 52429/65536 = 0.8

If the inicial value is -2, we have:

1: f(-2) = -1/4(-2) + 1 = 3/2

2: f(3/2) = -1/4(3/2) + 1 = 5/8

3: f(5/8) = -1/4(5/8) + 1 = 27/32

4: f(27/32) = -1/4(27/32) + 1 = 101/128

5: f(101/128) = -1/4(101/128) + 1 = 411/512

6: f(411/512) = -1/4(411/512) + 1 = 1637/2048

7: f(1637/2048) = -1/4(1637/2048) + 1 = 6555/8192

8: f(6555/8192) = -1/4(6555/8192) + 1 = 26213/32768

9: f(26213/32768) = -1/4(26213/32768) + 1 = 104859/131072

10: f(104859/131072) = -1/4(104859/131072) + 1 = 419429/524288 = 0.8

6 0

3 years ago