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Ilia_Sergeevich [38]

3 years ago

11

A circle is drawn within a square as shown. What is the best approximation for the area of the shaded region? Use 3.14 to approx

imate pi. 10.54 cm² 27.02 cm² 87.47 cm² 104.86 cm²

1 answer:

shusha [124]3 years ago

5 0

You didn't add the picture with the measurements, but I saw this somewhere else so I know the answer is 10.54

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Which shows the correct first step to solving the system of equations in the most efficient manner? 3 x + 2 y = 17. x + 4 y = 19

Anton [14]

Answer:

a.)x = negative 4 y + 19

Step-by-step explanation:

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Is 4d + (15 + 3d) equivalent to (4d + 15) + 3d ?

Akimi4 [234]

Answer:

Yes it is

Step-by-step explanation:

4d + 3d = 7d so 7d + 15 would be the expression for both except it would only be 3d + 4d = 7d and 7d + 15 is the same as the first expression that I got from evaluating 4d + (15 + 3d).

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4 years ago

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Answer the following:

jonny [76]

Answer:

As the product of the slop of both lines is -1.

$m_1\times m_2=-1$

$3\times \frac{-1}{3}=-1$

Therefore, the given equations are perpendicular.

Step-by-step explanation:

Given the equations

$-3x+y=-4$

$x+3y=6$

The slope-intercept form of the equation is

$y=mx+b$

where m is the slope and b is the y-intercept.

Writing both equations in the slope-intercept form

$-3x+y=-4$

$y=3x-4$

So by comparing with the slope-intercept form we can observe that

slope of equation = 3

i.e.

$m_1=3$

also

$x + 3y = 6$

$3y\:=\:6-x$

$y=-\frac{1}{3}x+2$

So by comparing with the slope-intercept form we can observe that

the slope of equation = -1/3

i.e.

$m_2=-\frac{1}{3}$

as

The slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

so

The slope $m_2$ is the negative reciprocal of the slope $\:m_1$

Also, the product of two perpendicular lines is -1.

i.e.

$m_1\times m_2=-1$

VERIFICATION:

It is clear that the product of the slop of both lines is -1.

$m_1\times m_2=-1$

$3\times \frac{-1}{3}=-1$

Therefore, the given equations are perpendicular.

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3 years ago

how many different ways could 3 girls and 3 boys form a line if the line must alternate boys and girls

mariarad [96]

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3 years ago

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