Answer:
0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Mean of 0.6 times a day
7 day week, so 
What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

In which




So

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Answer:x = 164686.592598
Step-by-step explanation:
219379.01−x/x = 0.3321
−x+219379.01/x = 0.3321
Step 1: Multiply both sides by x.
−x+219379.01≈0.3321x
−x+219379.01 − 0.3321x = 0.3321x−0.3321x (Subtract 0.3321x from both sides)
−1.3321x + 219379.01 = 0
−1.3321x + 219379.01 − 219379.01 = 0 − 219379.01 (Subtract 219379.01 from both sides)
−1.3321x = −219379.01
−1.3321x/−1.3321 = −219379.01/−1.3321
(Divide both sides by -1.3321)
x = 164686.592598
Answer:
540 degrees
Step-by-step explanation:
Answer:
Step-by-step explanation:divide 12/10 and 24/10. The larger answer will tell you the slower ant... I’m pretty sure