Answer:
The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>
Step-by-step explanation:
Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.
We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

Since, given the difference of the squares of the numbers is 5 that is 
And the product of the numbers is 6 that is 
Using identity, we have,

Substitute, we have,

Simplify, we have,


Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169
Answer:
168 miles.
Step-by-step explanation:
5/7x+40+0.75x−118=x
Step 1: Simplify both sides of the equation.
5/7x+40+0.75x−118=x
5/7x+40+0.75x+−118=x
(5/7x+0.75x)+(40+−118)=x(Combine Like Terms)
1.464286x+−78=x
1.464286x−78=x
Step 2: Subtract x from both sides.
1.464286x−78−x=x−x
0.464286x−78=0
Step 3: Add 78 to both sides.
0.464286x−78+78=0+78
0.464286x=78
Step 4: Divide both sides by 0.464286.
0.464286x/0.464286=78/0.464286
x=168
Divide 4w to every term separately.


48/4 = 12
w^3/w = w^2
So our first term is 12w^2.
128/4 = 32
w^2/w = w
So our second term is 32w.
4w/4w = 1
Anything divided by itself is 1.
-1/4w, this can't be simplified further, so this is our last term.
So we have: