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Oduvanchick [21]
2 years ago
11

Law of Sines (please help!)

Mathematics
1 answer:
love history [14]2 years ago
5 0
Hope this helps! :))))

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HELP ME PLEASE !!!!!!!!!!!!!!!!!!!!!!!!!!!
scoray [572]
7x-3=60
7x=63
x=9

11y+5=60
11y=55
y=11

hope this helps!!!
5 0
3 years ago
Solve for x. 2x + 9 = 33 What is the answer?<br><br> A 7.5<br><br> B 12<br><br> C 21<br><br> D 84
Valentin [98]
B, because you subtract 9 from both sides(2x-9 leaves 2x by itself then 33-9=24), which leaves you with 2x=24 the you divide everything by 2 which leaves you with x=12

8 0
3 years ago
Read 2 more answers
Which inequality best represents that ice cream at −2°C is cooler than ice cream at 4°C?
Luda [366]
Because it’s negative witch means it’s colder and the 4 is higher Bc it isn’t negative
8 0
3 years ago
Your height is 5 feet and 1 5/8 inches. Your friend’s height is 5.6 feet. Who is taller?
Alex Ar [27]
Not your friend you cause if you add 5 ft+1 5/8 it’s gonna be more than 5.)
7 0
3 years ago
The ideal width of a safety belt strap for a certain automobile is 6 cm. The actual width can vary by at most 0.45 cm. Write an
OlgaM077 [116]

Answer:

|x-6|\le 0.45

x\in [5.55,6.45]

Step-by-step explanation:

<u>Absolute Value Inequality</u>

Assume the actual width of a safety belt strap for a certain automobile is x. We know the ideal width of the strap is 6 cm. This means the variation from the ideal width is x-6.

Note if x is less than 6, then the variation is negative. We usually don't care about the sign of the variation, just the number. That is why we need to use the absolute value function.

The variation (unsigned) from the ideal width is:

|x-6|

The question requires that the variation is at most 0.45 cm. That poses the inequality:

|x-6|\le 0.45

That is the range of acceptable widths. Let's now solve the inequality.

To solve an inequality for an absolute value less than a positive number N, we write:

-0.45\le x-6 \le 0.45

This is a double inequality than can be easily solved by adding 6 to all the sides.

-0.45+6\le x \le 0.45+6

Operating:

5.55\le x \le 6.45

That is the solution in inequality form. Expressing in interval form:

\boxed{x\in [5.55,6.45]}

3 0
3 years ago
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