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Anna71 [15]
2 years ago
10

What is an algebraic expression for 5 times the sum of a number and 1

Mathematics
1 answer:
Lady_Fox [76]2 years ago
6 0
5 times the sum of a number and 1 would be:
5 • (n+1)
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Answer 16., 17., and 18., Text me after you have..!
musickatia [10]
I'm not quite sure how I'd attach a picture of my working so I'll explain the method.

16) I multiplied both 3.5 and 40 by ten so that I could divide them to find the number of servings. 35 divided by 400 is 11 remainder 15. If you then divide the remainder by 10 you get 11 servings and 1.5 ounces left over.

17) if you add up 26, 17, and 37 inches you get 80 inches, or just over 6 feet. Hence, he should buy an 8 foot length rod in order to have as little waste as possible.

18) 12.25 pounds is 196 ounces. Hence, the shipping rate at $0.26/ounce would end up being $50.96. From this we can see that the flat-rate box at $25 is less expensive.
4 0
2 years ago
Write the equation in slope intercept form of a line that goes through (4,9) and has a slope of 1/2
Vedmedyk [2.9K]

Answer:

y = \frac{1}{2} x + 7

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

here m = \frac{1}{2}, hence

y = \frac{1}{2} x + c ← is the partial equation

to find c substitute (4, 9) into the partial equation

9 = 2 + c ⇒ c = 9 - 2 = 7

y = \frac{1}{2} x + 7 ← equation in slope-intercept form


4 0
2 years ago
432,2=26<br>275,3=66<br>342,5=41<br>123,4=20<br>then <br>543,2=?​
Readme [11.4K]

Answer:

I think 543,2=24.

hope it helps

5 0
3 years ago
Find the height of a cuboid whose volume is 540 cu.cm and base area is 90 sq.cm .
EastWind [94]

Answer:

540/90=6

and is 6 cm

height is 6 cm

6 0
2 years ago
The local hamburger restaurant is famous for how quickly they can assemble a burger. The restaurant advertises that its constant
melisa1 [442]

The gievn equation is ,

t=11.3h\ldots(1)

where t is the time in seconds and h is the no.of hamburgers assembled.

put h = 2 in equation (1).

\begin{gathered} t=11.3\text{ (2)} \\ t=22.6 \end{gathered}

blank A assembles 2 hamburges in 22.6 seconds.

put h = 3 in equation (1)

\begin{gathered} t=11.3(3) \\ t=33.9 \end{gathered}

blank B assembles 3 hamburgers in 33.9 seconds.

put h = 5 in equation (1)

\begin{gathered} t=11.3(5) \\ t=56.5 \end{gathered}

blank C assembles 5 hamburgers in 56.5 seconds.

put h = 8 in equation (1)

\begin{gathered} t=11.3(8) \\ t=90.4 \end{gathered}

blank D assembles 8 hamburgers in 90.4 seconds.

3 0
10 months ago
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