Answer: good thinking
Step-by-step explanation:
here is the answer idk
So remember that the pythagorean theorem is a^2+b^2=c^2
c=18
legnth is 3 more than width
l=3+w
a=3+b
subsitute
(3+b)^2+b^2=18^2
expand
9+6b+b^2+b^2=324
subbtract 9 from both sides
6b+2b^2=313
subtract 313 from both sides
2b^2+6b-313=0
factor
use quadratic formula and get
b=11.1
subsitute
a=3+b
a=3+11.1
a=14.1
answer is 14.1 ft by 11.1 ft
Answer:
{
}
Step-by-step explanation:
We know that, by definition, the Domain is the set of all the x-coordinates of the ordered pairs and the Range is the set of all the y-coordinates of the ordered pairs.
Therefore, given
, you can observe that the set of all second elements of ordered pairs (the values of "y") is the following:
{
}
Therefore, we can conclude that if
, then the range is:
{
}
We are given a rectangle ABCD
A(-2, 3)
B(4, 6)
We are asked to find the slopes of sides BC, CD, and DA.
Let me first draw a rectangle to better understand the problem
Recall that the slope is given by


So the slope of side AB is

The sides BC and DA are perpenducluar to the side AB.
So their slopes will be

Substituting the value of slope of AB

The side CD is parallel to the side AB.
Parallel sides have equal slopes so

Therefore, the slopes of the rectangle ABCD are