6m+7n+5m−3n simplified
1 answer:
You might be interested in
We have that
2r−9≤−6------> 2r ≤ -6+9-------> 2r ≤ 3-----> r ≤ 1.5
the solution is the interval (-∞, 1.5]
using a graph tool
see the attached figure
2r−9≤−6------> 2r ≤ -6+9-------> 2r ≤ 3-----> r ≤ 1.5
the solution is the interval (-∞, 1.5]
using a graph tool
see the attached figure
Answer:
The maximum height is:
The ball reaches the ground in 1.79 s.
Step-by-step explanation:
We need to take the derivative and equal to zero to find the time at the maximum height.
(1)
Now, we just need to put t(max) into equation (1) to find h(max)
If we want to get the time when the ball reaches the ground we just need to equal h(t) to zero.
Let's solve this quadratic equation.
We will get two solutions and we must choose the positive value.
t1 = 1.79 u
t2 = -0.10 u
Therefore, the ball reaches the ground in 1.79 u.
I hope it helps you!