Answer:
250
Step-by-step explanation:
First with factorise the common factor out first, in this case, its 25.
25x6+25x4 = 25(6+4)
Now using of order of operations we will evaluate the bracket first.
25(6+4) = 25(10) = 25 x 10 = 250
Answer:
False (under assumption T(2,-3) means move it right 2 units and down 3 units).
Step-by-step explanation:
The statement is false.
T(2,-3) means move the point right 2 (so plus 2 on the x-coordinate) and down 3 units (so minus 3 on the y-coordinate).
So (1,6) will become (1+2,6-3)=(3,3) after the translation.
The point (1,12) will become (1+2,12-3)=(3,9).
If the statement were "Under the translation T(2,-3) the point (1,12) will become (3,9)", then it would be true.
Or!
If the statement were "Under the translation T(2,3) the point (1,6) will become (3,9)", then it would be true.
Answer:
7/20
Explanation:
In order to do this, you must first simplify all the equations to the simplest forms. Do this by simplifying 3/6 to 1/2. We know this because 3 is half of 6, therefore it would reduce down to 1/2. 7/10 is already simplified; we know this because 7 is a prime number and can’t do down any further
Now, multiply the two fractions buy multiplying the numerators and denominations together. In other words, 1 x 7 is 7 so your numerator is 7, and 2 x 10 is 20 so your denominator is 20.
We have been given that Tim spends about 1/3 of each weekday sleeping and about 7/24 of each weekday in school. And we need to find what fraction of the weekday does Tim spend either sleeping or in school.
This means that we need to find the time he spends in sleeping when he is in the school.
Therefore, we have to add the time he spends in sleeping and the time he spends in school.
Therefore, required fraction is given by

Now in order to add the fractions, we have to make the denominator same.
Multiply the numerator and denominator of first fraction by 8 to make the same denominator.

Now, we have the same denominator hence, we can add the numerator


Therefore, Tim spends 15/24 hours each weekday sleeping in the school.