The circumcenter is the center of the circle which goes through the triangle's vertices, so the circumcenter of the triangle and the center of that circumscribed circle MUST be the same point.
The same goes for the incenter and the center of the inscribed circle, though these will not, in general, be the same point as the circumcenter.
Answer:
HI ≈ 12.22
Step-by-step explanation:
tan I = GH / HI
tan 42° = 11 / HI = 0.90
HI = 11/0.90 = 12.22
Answer:
Step-by-step explanation:
Given that angle A is in IV quadrant
So A/2 would be in II quadrant.
sin A = -1/3
cos A = 
(cos A is positive since in IV quadrant)
Using this we can find cos A/2
8. It is divisible by both 32 and 40.
Use the side lengths! C and D have lengths of 3 and heights of 4.
Also use how far away they are from the axis.
Both C and D are 2 away from each axis on the end point.
This also goes with A.
However, B does not seem to be congruent in the sense of (coordinates)
It is the same length and height.
