Answer:
All real numbers
Step-by-step explanation:
The domain of the function represented by f(x) = x + 1 is the all real numbers as there is only addition involved in the function so putting any number as input will not lead the function to infinity.
Answer:
fits under statistics category (also probability or math :\)
Answer:
Step-by-step explanation:
The GCF doesn't have to be a number. In this case, it is -y because both the -2xy and -9y share it. It's also easier when you take out a negative. Once you take the GCF out, your new expression should be:
When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729
The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90
A) The probability of a word containing two of each of the letters is 90/729 = 10/81
The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1
B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.
_____
These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
Answer:
y = 2x + 1 --> linear
y = -4x + 7 --> non-linear
Not a solution for linear system.
Step-by-step explanation:
for (a), y = 2x+1, substitute the x and y values. keep in mind, that in a linear pair, (x, y). So, for the first equation you get:
7 = 2x3 + 1. This is correct, because 6 + 1 is 7. Therefore, (a) is linear.
for (b), we have to substitute our values again. You get:
7 = -4x3 + 7, which is
7 = -12+7, which is not true. So, (b) is not linear.
This means that for the linear pair (3, 7), it does not satisfy both equations, which means that it is not a solution for the linear system.
