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nikdorinn [45]
3 years ago
14

A flagpole that is 30 feet tall casts a shadow that extends 42 feet from the base of the flagpole. What is the distance from the

top of the flagpole to the end of the shadow?
Mathematics
1 answer:
uranmaximum [27]3 years ago
6 0
It’s the hypotenuse, so you would do a^2 + b^2 = c^2, let a equal 30 feet and let b equal 42 feet. hope this helps
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Step-by-step explanation:

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A basketball was originally priced at $25, but Tucker waited to buy it until the basketball was on sale for 20% off. If he paid
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Answer:

The answer to your question is $21.0

Step-by-step explanation:

Data

Original price = $25

Discount = 20%

Taxes = 5%

Process

1.- Calculate the price with the discount

                     $25 ------------------- 100%

                        x   -------------------   20%

                        x = (20 x 25) / 100

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2.- Calculate the price after taxes

                     $20 ---------------------- 100%

                         x  -----------------------   5%

                       x = (5 x 20) / 100

                       x = 100 / 100

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At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us
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Answer:

<u>The expected value of every ticket is a loss of $ 1.35</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

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  • Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
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Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

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<u>The expected value of every ticket is a loss of $ 1.35</u>

8 0
3 years ago
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