Answer: 3t²(2st⁷ - s⁶ - 2t⁵)
<u>Step-by-step explanation:</u>
5s⁶t² + 6st⁹ - 8s⁶t² - 6t⁷ <em>5s⁶t² and - 8s⁶t² are like terms which = -3s⁶t² when combined</em>
= 6st⁹ - 3s⁶t² - 6t⁷ <em>next, factor out the GCF of 3t²</em>
= 3t²(2st⁷ - s⁶ - 2t⁵)
This distance can be expressed as 3.84×
m.
What is distance with example?
- Distance is a scalar quantity.
- The distance of an object can be defined as the complete path travelled by an object.
Given the distance between the earth and the moon is 384000km
Representing in exponential notation,
=384000×1000m [∵1km=1000m]
=384×
m
=3.84×
m
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<u>The correct question is -</u>
The distance between the Earth and the moon is approximately 384000 km. this distance can be expressed as ____m.
Answer:
2min per lap
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
Answer:X/3X=3
We move all terms to the left:
X/3X-(3)=0
Domain of the equation: 3X!=0
X!=0/3
X!=0
X∈R
We multiply all the terms by the denominator
X-3*3X=0
Wy multiply elements
X-9X=0
We add all the numbers together, and all the variables
-8X=0
X=0/-8
X=0
Step-by-step explanation: