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Zolol [24]
4 years ago
11

Describe the interaction with the sun and producers

Physics
1 answer:
bagirrra123 [75]4 years ago
4 0

Answer: the sun's rays is one of the raw Materials recquired by plants to make food

Explanation:plants trap light used in splitting water into hydrogen ions and oxygen molecules

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A box rests on the floor. If you pull sideways on the box with a 300 N force, but don't move it, what is the magnitude of the fr
Dahasolnce [82]

The magnitude of the frictional force is B) 300 N

Explanation:

For this problem, we just have to consider the forces acting on the box in the horizontal direction.

There are only two forces in this direction:

- The pull applied by the man, of magnitude F=300 N, forward

- The frictional force, F_f, acting backward

So the equation of motion for the box is

F-F_f = ma

where

m is the mass of the box

a is its acceleration

However, the box is at rest, so its acceleration is zero:

a = 0

This means therefore that

F-F_f=0

And so the magnitude of the frictional force is equal to the pulling force:

F_f = F = 300 N

Learn more about friction:

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brainly.com/question/2235246

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5 0
3 years ago
A box with a mass of 20 kilograms is sliding down a ramp tilted at an angle θ of 30° to the horizontal. Determine the accelerati
Bumek [7]

The acceleration of the box as it slides down the ramp is 4.9 m/s².

<h3>What is the acceleration of the box down the incline?</h3>

The acceleration of the box down the incline is determined by applying Newton's second law of motion as shown below;

F - Ff = ma

where;

  • F is the parallel force on the box
  • Ff is the frictional force on box = 0
  • m is the mass of the box
  • a is the acceleration of the box

F - 0 = ma

F = ma

mg sinθ = ma

g sinθ = a

where;

  • g is acceleration due to gravity
  • θ is the angle of inclination of the incline

a = 9.8 x sin(30)

a = 4.9 m/s²

Learn more about acceleration here: brainly.com/question/14344386

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8 0
2 years ago
A 600 g model rocket is on a cart that is rolling to the right at a speed of 4.0 m/s. The rocket engine, when it is fired, exert
murzikaleks [220]

Answer:

The rocket should be launched when the cart is 13.48m away from a point directly below the hoop.

Explanation:

Step 1: Data given

mass of the rocket = 600 grams

speed = 4.0 m/s

Step 2: Calculate weight

Fw = mg

with Fw = the weight (in Newton)

with m = the mass (in kg)

with g = the acceleration due to gravity (9.81 m/s²).

Fw = (0.600 kg)(9.81 m/s²)  = 5.886 N

Step 3: Calculate force available to provide acceleration

The rocket engine, when it is fired, exerts a 8.0 AND vertical thrust on the rocket.

5.886 N of that force will be used to counter the rocket's weight, leaving 2.114 N of force available to provide acceleration.  

Step 4: Calculate the rocket's upward acceleration:

Fnet = m*a

With Fnet = the net force (the force that remains after the rocket's weight is compensated)

with a = the rocket's acceleration (in m/s²)

2.114 N = (0.600 kg)*a

a = 3.52 m/s²  = the rocket's upward acceleration

Step 5: Calculate how long it will take to rise 20 meters into the air.

Δy = v0*t + 1/2 at²

with v0 = 0m/s

Δy = 1/2 at²

20 m = 1/2(3.52)t²

20 m = (1.76 m/s²)t²

11.36 = t²

t = 3.37 s

This means the rocket will take 3.37 seconds to reach the hoop.  It should be launched when the cart is 3.37 seconds away from being directly beneath the hoop.  

Step 6: Calculate the distance

v = Δx / t

4.0 m/s = Δx / 3.37 s

Δx = 13.48 m

The rocket should be launched when the cart is 13.48m away from a point directly below the hoop.

8 0
4 years ago
An object initially at rest experiences an acceleration of 9.8 m/s2 how much time will it take it to achieve a velocity of 58 m/
Ber [7]

Answer:

The time required by object to achieve velocity 58 m/s is 5.918 second.

Given:

acceleration = 9.8 \frac{m}{s^{2} }

Initial velocity = 0 m/s

final velocity = 58 m/s

To find:

Time required by object = ?

Formula used:

According to first equation of motion is given by,

v = u + at

Where, v = final velocity

u = initial velocity = 0 (Given The particle is at rest initially)

a = acceleration

t = time

Solution:

According to first equation of motion is given by,

v = u + at

Where, v = final velocity

u = initial velocity = 0 (Given The particle is at rest initially)

a = acceleration

t = time

58 = 0 + 9.8 (t)

t = \frac{58}{9.8}

t = 5.918 s

The time required by object to achieve velocity 58 m/s is 5.918 second.



8 0
4 years ago
Definition of angle of incidence​
Nadusha1986 [10]
The definition of incidence is In geometric optics, the angle of incidence is the angle between a ray incident on a surface and the line perpendicular to the surface at the point of incidence, called the normal.
3 0
3 years ago
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