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2 years ago

How many atoms are present in 2 moles of chromium?

Physics

1 answer:

Alex Ar [27]2 years ago

3 0

Answer:

1 mole = 6.02E23 molecules

2 moles = 12.04E24 molecules

This is a molecular count (assuming 1 atom per molecule) that will be # atoms)

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Which state helps produce light in fluorescent light bulbs?

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The answer is D plasma

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3 years ago

True or False <br> Most magnets are made<br> from 100% aluminum

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Answer:

True

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2 years ago

Read 2 more answers

Select the correct answer from each drop-down menu. complete the sentence to describe the distance and ruler postulates. between

Tresset [83]

This question is an illustration of the distance postulate.

<h3>What is distance postulate ?</h3>

The distance between any two different points equates to a single positive real integer, according to the postulate of distance.

The full text is: The distance is a positive unique integer between every pair of different locations.

Consider two separate points A and B as an example.

The distance between A and B is the integer that represents the size of A and B.

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brainly.com/question/16765541

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2 years ago

What’s the acceleration if the average velocity is 3.5 and the time is 8.7

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3 years ago

An element has the following natural abundances and isotopic masses: 90.92% abundance with 19.99 amu, 0.26% abundance with 20.99

sashaice [31]

<u>Answer:</u> The average atomic mass of the given element is 20.169 amu.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of the isotopes each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

We are given:

For isotope 1:

Mass of isotope 1 = 19.99 amu

Percentage abundance of isotope 1 = 90.92 %

Fractional abundance of isotope 1 = 0.9092

For isotope 2:

Mass of isotope 2 = 20.99 amu

Percentage abundance of isotope 2 = 0.26%

Fractional abundance of isotope 2 = 0.0026

For isotope 3:

Mass of isotope 3 = 21.99 amu

Percentage abundance of isotope 3 = 8.82%

Fractional abundance of isotope 3 = 0.0882

Putting values in equation 1, we get:

$\text{Average atomic mass}=[(19.99\times 0.9092)+(20.99\times 0.0026)+(21.99\times 0.0882)]$

$\text{Average atomic mass}=20.169amu$

Hence, the average atomic mass of the given element is 20.169 amu.

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3 years ago