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Elanso [62]
2 years ago
12

Emeka carried out a reaction in which a gas was given off. He followed the progress of the reaction by measuring the mass of the

reaction vessel over time. After 5 minutes the mass of the reaction vessel had decreased from 120g to 114.5g. Calculate the rate of this reaction.
Physics
1 answer:
pickupchik [31]2 years ago
6 0

Answer:

17.5

or

1.1 g/min

I know it's one of these, try getting a second opinion

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When the distance between two interacting objects doubles, the gravitational force is
Umnica [9.8K]

The gravitational force will be one quarter.

The gravitational force between two objects is given by the formula

F=GMm/r^2

here, r is the distance between the objects.

Thus the gravitational force is inversely proportional to the square of the distance between the objects, Therefore if the distance between two objects is doubled the force will be one quarter.

5 0
3 years ago
When a student stands on a rotating table,the frictional force exerted on the student by the table is?
lakkis [162]

Answer:

Less

Explanation:

because static friction is more than rolling friction

7 0
3 years ago
Suppose your walking speed is 2m/s in a period of 1 s . What is your acceleration?
Veronika [31]

Answer:

<h2>2 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

v is the velocity

t is the time taken

From the question we have

a =  \frac{2}{1}  \\

We have the final answer as

<h3>2 m/s²</h3>

Hope this helps you

6 0
3 years ago
Consider a satellite in a circular orbit around the Earth. If it were at an altitude equal to twice the radius of the Earth, 2RE
Elenna [48]

Answer:

v=\sqrt{\frac{gR_E}{2}}

Explanation:

Satellites experiment a force given by Newton's Gravitation Law:

F=\frac{GMm}{r^2}

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We also know from Newton's 2nd Law that <em>F=ma, </em>so putting both together we will have:

ma=\frac{GMm}{r^2}

a=\frac{GM}{r^2}

If we are on the surface of the Earth, the acceleration would be g and r=R_E (Earth's radius):

g=\frac{GM}{R_E^2}

Which we will write as:

gR_E^2=GM

If we are on orbit the acceleration is centripetal (a=\frac{v^2}{r}), so we have:

\frac{v^2}{r}=a=\frac{GM}{r^2}=\frac{gR_E^2}{r^2}

v^2=\frac{gR_E^2}{r}

v=\sqrt{\frac{gR_E^2}{r}}

And if this orbit has a radius r=2R_E we have:

v=\sqrt{\frac{gR_E^2}{2R_E}}=\sqrt{\frac{gR_E}{2}}

3 0
3 years ago
Read 2 more answers
Question is in PNG please someone help!
zhuklara [117]

Answer:

2.a.i think it's heat and kinetic

2.b.i think kinetic

3 0
3 years ago
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