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Elanso [62]
2 years ago
12

Emeka carried out a reaction in which a gas was given off. He followed the progress of the reaction by measuring the mass of the

reaction vessel over time. After 5 minutes the mass of the reaction vessel had decreased from 120g to 114.5g. Calculate the rate of this reaction.
Physics
1 answer:
pickupchik [31]2 years ago
6 0

Answer:

17.5

or

1.1 g/min

I know it's one of these, try getting a second opinion

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A 30 ohm resistor and a 20 ohm resistor are
Reptile [31]

The current that would pass through the 30 ohms resistor is 2 A.

<h3>What is electric current?</h3>

Electric current is the rate of flow of electric charge round a conductor.

To calculate the electric current that would pass through the 30 ohms resistor, we use the formula below

Formula:

  • I = V/Rt........... Equation 1

Where:

  • I = Electric current passing through the 30 ohms resistor
  • V = Voltage
  • Rt = Total or effective resistance of the resistors.

From the question,

Given:

  • V = 100 volts
  • Rt = (30+20) ohms (since both resistors are connected in series)
  • Rt = 50 ohms

Substitute these values into equation 1

  • I = 100/50
  • I = 2 A

Hence, The current that would pass through the 30 ohms resistor is 2 A.

Learn more about electric current here: brainly.com/question/1100341

8 0
2 years ago
Which volcanic hazard can block the sunlight and temporarily cool the Earth’s surface?
BaLLatris [955]
If a volcano epulses massive amounts of dust into the atmosphere, those two things will/can happen.
The events will last until the dust lays down on the earth.

8 0
3 years ago
Read 2 more answers
In a collision, a 25.0 kg mass moving at 3.0 m/s transfers all of its momentum to a 5.0 kg mass.
nadezda [96]

Answer:

Explanation:

The momentum of the 25 kg mass is

p=mv

p=25kg*3m/s= 75kg*m/s

If this whole momentum of the object is transferred to the 5.0 kg object then according to the law of conservation of momentum, the momentum of the 25.0 kg object must be transferred to the 5.0 kg object:

75kg*m/s = 5.0kg*v

v=\dfrac{75}{5}

\boxed{v=15m/s}

8 0
3 years ago
Given: F = k· m. g<br> Solve for "k"
gulaghasi [49]

Answer:

F = kmg \\ k =  \frac{F}{mg}

8 0
3 years ago
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A particle moves along the x-axis so that its velocity at anytime is t greater than or equal to 0 is given by v(t)=1-sin(2pi t)
UkoKoshka [18]
A) We differentiate the expression for velocity to obtain an expression for acceleration:
v(t) = 1 - sin(2πt)
dv/dt = -2πcos(2πt)
a = -2πcos(2πt)

b) Any value of t can be plugged in as long as it is greater than or equal to 0. 

c) we integrate the expression of velocity to find an expression for displacement:
∫v(t) dt = ∫ 1 - sin(2πt) dt
x(t) = t + cos(2πt)/2π + c
x(0) = 0
0 = = + cos(0)/2π + c
c = -1/2π
x(t) = t + cos(2πt)/2π -1/2π
5 0
3 years ago
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