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Nat2105 [25]
3 years ago
11

For a class activity, your group has been assigned the task of generating a quiz question that requires use of the formula for c

onditional probability to compute P(B | A). Your group comes up with the following question "If P(A and B) = 0.40 and P(A) = 0.20, what is the value of P(B | A)?" What is wrong with this question? Hint: Consider the answer you get when using the correct formula, P(B | A) = P(A and B)/P(A).
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
3 0

Answer: P(A and B) is greater than P(A)

P(A and B) should be smaller than P(A).

Step-by-step explanation:

Given :  P(A and B) = 0.40

P(A) = 0.20

Using the given formula of the conditional probability will be

P(B|A)=\dfrac{\text{P(A and B)}}{P(A)}\\\\=\dfrac{0.40}{0.20}=2

But we know that the probability of any event cannot be more than 1.

Also, the probability of the intersection must be less than the probability of individual event.

Thus , in the given question P(A and B) must be smaller than P(A).

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Answer:

11 positive integers can be expressed.

Step-by-step explanation:

Consider the provided information.

The number of possible prime numbers are 5,7,11,and 13.

There are 4 possible prime numbers.

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The formula to calculate combinations is: ^nC_r=\frac{n!}{r!(n-r)!}

The number of ways are:

^4C_2+^4C_3+^4C_4=\frac{4!}{2!(4-2)!}+\frac{4!}{3!(4-3)!}+\frac{4!}{4!}

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Hence, 11 positive integers can be expressed.

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