100 POINTS GIVE AWAY IS BACK!!!

Kryger [21]

Answer:

1. -5.5 2. 5 3. 5, 5.5

Step-by-step explanation:

For #1 just look at what point it would be towards the y- axis.

For #2 you want to kinda estimate what it would be between.

And lastly #3 they want to see the exact coordinates for Q so, look at the x axis first they the y axis. Remember Run then Jump

4 0

2 years ago

What is the value of x in this equation<br> [x+17]=20x

Digiron [165]

Answer:

0.90=X or 0.89=X

If it's not right, then i'm sorry :)

3 0

3 years ago

The diameter of a flour tortilla is 12 inches. What is the area to the nearest hundredth?

dimaraw [331]

3.14*d

3.14*12= 37.68

Rounded to the nearest hundredth would be 37.7

4 0

3 years ago

Read 2 more answers

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

What is the answer to 1.75g x 1000mg/1g?

Lerok [7]

1750mg in 1.75g just move the decimal place over three places. so its 1750mg

8 0

3 years ago