Here's a pattern to consider:
1+100=101
2+99=101
3+98=101
4+97=101
5+96=101
.....
This question relates to the discovery of Gauss, a mathematician. He found out that if you split 100 from 1-50 and 51-100, you could add them from each end to get a sum of 101. As there are 50 sets of addition, then the total is 50×101=5050
So, the sum of the first 100 positive integers is 5050.
Quick note
We can use a formula to find out the sum of an arithmetic series:

Where s is the sum of the series and n is the number of terms in the series. It works for the above problem.
60 ≥ 35 + 5t
<u>-35 </u><u> </u><u>-35 </u>
<u>25</u> ≥ <u>5t</u>
5 5
t≤5
his mistake was that he used ≤ for at least instead of using ≥. so at end, when I solved, I saw that Sven should spend 5 minutes or less on each scale.
Trick question. For the reflections given in the problem statement, the x-coordinate doesn't change. The number that goes in the green box is 1.
If you nee solving it will be:
c^6(-3c^5)^2
c^6(3c^5)^2
c^6·3^2(c^5)^2
c^6·9(c^5)^2
c^6·9c^10
9c^6c^10
9c^6+10
9c^16
So the answer is:
9c^16
(9c to the power of 16)
Sorry I was late..
The measure of a triangle is 180 degrees. In other words the sum of the angles of a triangle is 180 degrees
To solve for x set all of the expressions of angles equal to 180 and isolate x
11x - 3 + 7x + 5 + 13x - 8 = 180
31x + (- 6 + 6) = 180 + 6
31x/31 = 186 / 31
x = 6
To find the measure of each angle plug 6 into the x into each individual expression
Hope this helped!