What element is found in liver and red blood cells and is needed to prevent anemia

Chemistry

2 answers:

Lana71 [14]2 years ago

7 0

Iron is the element found in the liver to prevent anemia

irina [24]2 years ago

4 0

Iron is the element found in the liver and red blood cells, needed to prevent anemia

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Which option explains how purple pigments make some flower petals purple?

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How many grams of silver nitrate are needed to react with 156.2g of sodium sulfide to produce 595.8g of silver sulfide and 340.0

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Before proceeding, we should write the reaction equation to better understand what is happening:
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3 years ago

Which of the following could you do to increase the strength of an electromagnet? decrease the number of windings decrease the e

IgorLugansk [536]

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Read 2 more answers

When methyloxirane is treated with HBr, the bromide ion attacks the less substituted position. However, when phenyloxirane is tr

konstantin123 [22]

Answer:

See explanation and picture below

Explanation:

First, in the case of methyloxirane (Also known as propilene oxide) the mechanism that is taking place there is something similar to a Sn2 mechanism. Although a Sn2 mechanism is a bimolecular substitution taking place in only step, the mechanism followed here is pretty similar after the first step.

In both cases, the H atom of the HBr goes to the oxygen in the molecule. You'll have a OH⁺ in both. However, in the case of methyloxirane the next step is a Sn2 mechanism step, the bromide ion will go to the less substitued carbon, because the methyl group is exerting a steric hindrance. Not a big one but it has a little effect there, that's why the bromide will rather go to the carbon with more hydrogens. and the final product is formed.

In the case of phenyloxirane, once the OH⁺ is formed, the next step is a Sn1 mechanism. In this case, the bond C - OH⁺ is opened on the side of the phenyl to stabilize the OH. This is because that carbon is more stable than the carbon with no phenyl. (A 3° carbon is more stable than a 2° carbon). Therefore, when this bond opens, the bromide will go there in the next step, and the final product is formed. See picture below for mechanism and products.

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3 years ago