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2 years ago

E=hv h= 6.62 x 10^-34 m^2 kg/ s

Chemistry

1 answer:

Drupady [299]2 years ago

7 0

v=5.0×10^12Hz

$\\ \sf\longmapsto E=hv$

$\\ \sf\longmapsto E=6.626\times 10^{-34}Js\times 5\times 10^12s^{-1}$

$\\ \sf\longmapsto E=33.13\times 10^{-22}J$

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$\Delta H=\frac{q}{n}$

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$\Delta H$ = enthalpy change = ?

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Molar mass of NaOH = 40 g/mole

$\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{3.25g}{40g/mole}=0.0812mole$

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