Question

Use the distance formula to find the distance between each pair of points. Round your answers to the nearest hundredths place W (-3,-5) and T (2,-2)

Answer 1

Answer:

√34

Step-by-step explanation:

$W (-3,-5) =(x_1,y_1)\\T (2,-2)=(x_2,y_2)\\\\d = \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\\d=\sqrt{\left(2-\left(-3\right)\right)^2+\left(-2-\left(-5\right)\right)^2}\\\\d=\sqrt{\left(2+3\right)^2+\left(-2+5\right)^2}\\\\d=\sqrt{5^2+3^2}\\\\d=\sqrt{25+9}\\\\d=\sqrt{34}$

Answer 2

Answer:

The answer is

5.83 units

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} }$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

W (-3,-5) and T (2,-2)

The distance between them is

$|WT| = \sqrt{ ({ - 3 - 2})^{2} + ( { - 5 + 2})^{2} } \\ = \sqrt{ ({ - 5})^{2} + ( { - 3})^{2} } \: \: \: \\ = \sqrt{25 + 9} \\ = \sqrt{34} \: \: \: \: \: \: \: \: \\ = 5.830951$

We have the final answer as

5.83 units to the nearest hundredth

Hope this helps you