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Sloan [31]
3 years ago
9

Cody want to compare how students in two grades use the school library. For one week he records the number of books taken out ea

ch day. Which statement is true based on Cody’s example.

Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

First sencente is the correct one

Step-by-step explanation:

First we can find the total books and the average book per day for each grade:

7th grade: total of 6 + 6 + 7 + 11 + 5 = 35 books

average: 35 / 5 = 7 books per day

8th grade: total of 4 + 5 + 10 + 10 + 16 = 45 books

average: 45 / 5 = 9 books per day

First sencente: true, 8th grade has 9 books per day and 7th grade has 7 books per day

Second sentence: false, 8th grade has 45 books and 7th grade has 35 books

Third sentence: false, it is 6.

Fourth sentence: false, range for 7th grade is 5, range for 8th grade is 12

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What is the probability that the sample mean life span of 64 calculators from Caseo will exceed the sample mean life span of 81
musickatia [10]

Answer:

it would be 64-81  than answer devide by 6.

8 0
3 years ago
I don't understand rational and irrational numbers
PSYCHO15rus [73]

A rational number is a number which can be expressed as a fraction whose numerator and denominator are both integers and whose denominator is not equal to zero. Rational numbers include all integers, fractions, mixed numbers, and some decimal numbers.

 

Note : All terminating and repeating decimal numbers are rational numbers because those numbers can be expressed as a fraction. On the other hand, a non repeating number and non terminating decimal, like square root of 2, is an irrational number.  


\dfrac{7}{16} \ as \ a \ decimal = 0.4375


Set \ up \ the \ long \ division. 


Calculate \ 70 \div 16, \ which \ is \ 4  \ with \ a \ remainder \ of \ 6.




Bring \ down \ 0, so \ that \ 60 \ is \ large \ enough \ to \ be  \ divided \ by \ 16.




Calculate \ 60 \div 16, which \ is \ 3 \ with \ a  \ remainder \ of \ 12.




Bring \ down \ 0, so \ that \ 120 \ is \ large \ enough \ to \ be \ divided \ by \ 16.




Calculate \ 120 \div 16, which \ is \ 7 \ with \ a \ remainder \ of \ 8.




Bring \ down \ 0, so \ that \ 80 \ is \ large \ enough \ to \ be \ divided \ by \ 16.



Calculate \ 80 \div 16, which \ is \ 5. 

<span>
</span>

Decimal = 0.4375&#10;

4 0
3 years ago
An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you th
aliya0001 [1]

Answer:

0.227 = 22.7% probability that the mean printing speed of the sample is greater than 18.12 ppm.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 17.42 ppm and a standard deviation of 3.25 ppm.

This means that \mu = 17.42, \sigma = 3.25

Sample of 12:

This means that n = 12, s = \frac{3.25}{\sqrt{12}}

Find the probability that the mean printing speed of the sample is greater than 18.12 ppm.

This is 1 subtracted by the p-value of Z when X = 18.12.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{18.12 - 17.42}{\frac{3.25}{\sqrt{12}}}

Z = 0.75

Z = 0.75 has a pvalue of 0.773.

1 - 0.773 = 0.227

0.227 = 22.7% probability that the mean printing speed of the sample is greater than 18.12 ppm.

4 0
3 years ago
Please help me with this. I will give brainliest.
Temka [501]

Answer:

do you still need this answered?

Step-by-step explanation:

7 0
3 years ago
Constant rate of change = 4<br> Y -intercept = 7
Levart [38]

Answer:

You would write it like -

y = 7 + 4x

or y = 4x + 7

8 0
3 years ago
Read 2 more answers
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