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Lina20 [59]
3 years ago
13

Using the distributive property, break apart 6x4 = 24

Mathematics
1 answer:
____ [38]3 years ago
8 0
6x8=
{6x 4} + {6x 4 }
= + =
24 24
48
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The question is in the image
Yuri [45]

Answer:

C. Carolyn did not subtract 4 from both sides of the equation.

Step-by-step explanation:

3x-2(x+2)=7 should be 3x-2x-4=7 not 3x-2x+4=7

3 0
3 years ago
Shirley had 9 baseball cards. She bought 2 packets of baseball cards, which gave her a total of 23 baseball cards.
Bond [772]
23-9= 14
14 divide by 2 = 7
so 7 baseball cards in a packet
8 0
3 years ago
Read 2 more answers
The price of A cup of coffee was $2.20 yesterday today the price rose to $2.55 find the percentage increase round your answer to
Anna11 [10]
.35 is the raise of the cup of coffee
4 0
3 years ago
A store has been selling 100 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
Sav [38]

Answer:

<em>The rebate should be $220</em>

Step-by-step explanation:

<u>Demand Curve</u>

It's the relationship between price (P) and quantity (Q) demanded a certain product or service.

(a) We need to find the function that relates both magnitudes assuming a linear equation. The equation of a line can be found with the point-point formula:

\displaystyle Q-Q_1=\frac{Q_2-Q_1}{P_2-P_1}(P-P_1)

Two sets of data are given: 100 Blu-ray disc players are sold a week at $600 each. The ordered pair for this condition is (P,Q)=(600,100).

The other point comes from the market survey: The number of units sold will increase by 80 (100+80=180) when the price goes down $40 (600-40=560). The new point is (P,Q)=(560,180)

We set up the equation of the demand

\displaystyle Q-100=\frac{180-100}{560-600}(P-560)

Rearranging

-40Q+4000=80P-44800

Or

80P+40Q=48800

Simplifying

2P+Q=1120

(b) The revenue function is Q times the price

R=Q.P

Solving the equation of the demand for P

\displaystyle P=\frac{1120-Q}{2}

Thus, the revenue is

\displaystyle R=Q\cdot \frac{1120-Q}{2}

\displaystyle R=\frac{1120Q-Q^2}{2}

(c) To find the optimum value of the revenue, we take the derivative of R and equate to 0

\displaystyle R'=\frac{1120-2Q}{2}=560-Q=0

Solving

Q=560 units a week

For which the revenue is

\displaystyle R=\frac{1120(560)-560^2}{2}

R=\$156,800

And the price is

\displaystyle P=\frac{1120-560}{2}=280

P=\$280

The rebate should be $600-$280=$220

4 0
3 years ago
What’s the rule? (Write a rule for the relationship between variables represented in each table.)
Anvisha [2.4K]
The rule is y = 3x + 1
4 0
3 years ago
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