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Gelneren [198K]
3 years ago
9

HELPPPPPPPP why is the answer D?

Mathematics
2 answers:
Marysya12 [62]3 years ago
8 0
We can solve for x by raising both sides to the -3 power (which is the reciprocal of -1/3):

(c^-1/3)^-3 = x^-3
c^1=x^-3
c=x^-3

Since the exponent on the x is a negative, we have to move it to the denominator to make it positive:

c= 1/x³
Sloan [31]3 years ago
4 0
I can hardly see the minus sign in front of the (1/3). Is it (c^ - 1/3)? If it is, then the relationship is 1/c^(1/3) = x 

This is where it gets very convoluted.  What I have written at the end of the first paragraph indicates an inverse relationship. As x goes up in value, c becomes smaller. To get c back in the numerator, the easiest way to do it is take the reciprocal of both sides.

What you get is c^1/3 = 1/x Now you can cube both sides.

c^(1/3)^3 = (1/x)^3
c^1 = 1^3 / x^3
c = 1 / x^3

D <<<<< answer. But that minus sign better be there.
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Simplify: j + 5 + 5c
irina [24]
The answer is 5
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j
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5 0
2 years ago
X(x+1)-1=4<br> ---<br> please help stuck on this question
Sloan [31]

Answer:

x=2

Step-by-step explanation:

use distributive property: x^2+2x-1=4

remove the -1 by adding 1 on both sides: x^2+2x=5

use the guadratic fromula:  ax²+bx+c=0

plug in the equation x^2+2x-5=0

a,b and c are the coefficients to plug into the formula

a=1, b=2, c=-1

Finally, you will find that x=2

8 0
2 years ago
Read 2 more answers
Se tiene un lote baldío de forma triangular bardeado. La barda de enfrente tiene una medida de 4 m,las otras dos bardas no es po
dybincka [34]

Answer:

a) La medida de la barda que está enfrente del ángulo 64° es de, aproximadamente, 6.4292m. b) El triángulo en cuestión <em>no es un triángulo rectángulo</em>, es decir, ninguno de sus ángulos internos es <em>recto </em>(90 grados sexagesimales). En estos casos, no se puede aplicar el Teorema de Pitágoras o la simple utilización de las razones trigonométricas; se aplican, en cambio, leyes para la resolución de triángulos oblicuángulos (o triángulos no rectángulos).

Step-by-step explanation:

Este problema no se puede resolver "aplicando sólo las razones trigonométricas o el teorema de Pitágoras" porque es sólo aplicable a <em>triángulos rectos</em>, es decir, uno de los ángulos del triángulo es recto o igual a <em>90</em> grados sexagesimales. Los dos restantes triángulos suman 90 grados sexagesimales, o se dice, son <em>complementarios</em>.

La resolución de triángulos que no son rectos (conocida en algunos textos como solución de problemas de triángulos oblicuángulos) pueden resolverse usando, la <em>ley de los senos (o teorema del seno)</em>, <em>ley de los cosenos</em> y <em>la ley de las tangentes</em>. El caso propuesto en la pregunta se ajusta a la <em>ley de los senos</em>:

\\ \frac{a}{\sin(\alpha)} = \frac{b}{\sin(\beta)} = \frac{c}{\sin(\gamma)}

Es decir, la razón entre el lado de un triángulo y el seno del ángulo que tiene frente a él es igual para todos los lados y ángulos del triángulo.

El triángulo de la pregunta no tiene un ángulo recto

La suma de los ángulos internos de un triángulo es de 180 grados sexagesimales:

\\ \alpha + \beta + \gamma = 180^{\circ}

En la pregunta tenemos que la suma de los dos ángulos propuestos es:

\\ 34^{\circ} + 64^{\circ} + \gamma = 180^{\circ}

\\ 98^{\circ} + \gamma = 180^{\circ}

Restando 98 grados sexagesimales a cada lado de la igualdad:

\\ 98^{\circ} - 98^{\circ} + \gamma = 180^{\circ} - 98^{\circ}

\\ 0 + \gamma = 180^{\circ} - 98^{\circ}

\\ \gamma = 82^{\circ}

Con lo que se deduce que no hay ningún ángulo recto en el triángulo propuesto y no se podría usar el Teorema de Pitágoras o simples razones trigonométricas para resolverlo.

Resolución del lado del triángulo

De la pregunta tenemos:

  • La barda de enfrente tiene una medida de 4m. El ángulo que está enfrente de esta barda (barda frontal) es de 34°.
  • No se sabe el valor del lado que está enfrente del ángulo de 64°, pero se puede calcular usando la Ley de los senos.

Digamos que:

\\ a = 4m, \alpha = 34^{\circ}

\\ b = x, \beta = 64^{\circ}

Entonces, aplicando la <em>Ley de los senos</em>:

\\ \frac{a}{\sin(\alpha)} = \frac{b}{\sin(\beta)}

Multiplicando a cada lado de la igualdad por \\ \sin(\beta)

\\ \frac{a}{\sin(\alpha)}*\sin(\beta) = \frac{b}{\sin(\beta)}*\sin(\beta)

\\ \frac{a}{\sin(\alpha)}*\sin(\beta) = b*\frac{\sin(\beta)}{\sin(\beta)}

\\ \frac{a}{\sin(\alpha)}*\sin(\beta) = b*1

\\ \frac{a}{\sin(\alpha)}*\sin(\beta) = b

Sustituyendo cada valor en la expresión anterior:

\\ b = \frac{a}{\sin(\alpha)}*\sin(\beta)

\\ b = \frac{4m}{\sin(34^{\circ})}*\sin(64^{\circ})

\\ b = 4m*\frac{0.8988}{0.5592}

\\ b = 6.4292m

En palabras, la medida de la barda que está enfrente del ángulo 64° es de, aproximadamente, 6.4292m.

El lado <em>c</em> puede obtenerse de manera similar considerando que \\ \gamma = 82^{\circ}.

6 0
2 years ago
Which of the following points could be added to the graph f(x)=-|x+3| to keep the graph a function?
sasho [114]

None of the points could be added to the graph f(x)=-|x+3| to keep the graph a function

<h3>How to determine the point?</h3>

The equation of the function is given as:

f(x) = - |x + 3|

The points are given as:

(0, 3) and (-3, -6)

When x = 0, we have:

f(0) = - |0 + 3|

f(0) = -3 --- different y value from (0, 3)

When x = -3, we have:

f(-3) = - |-3 + 3|

f(-3) = 0 --- different y value from (-3, -6)

This means that the x values point to different y values (this does not represent a function)

Hence, none of the points could be added to the graph f(x)=-|x+3| to keep the graph a function

Read more about functions and relations at:

brainly.com/question/2328150

#SPJ1

6 0
2 years ago
An ancient Chinese candle clock tells the amount of time that has passed by the amount of wax that has been melted off the candl
rjkz [21]
Two candles=8 hours=8*60=480 minutes
4 inch is 4/12 of a candle, 4/12 of 4 hours=16/12=4/3 hours=80 minutes
so the total minutes are 480+80=560 
8 0
3 years ago
Read 2 more answers
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