I can hardly see the minus sign in front of the (1/3). Is it (c^ - 1/3)? If it is, then the relationship is 1/c^(1/3) = x
This is where it gets very convoluted. What I have written at the end of the first paragraph indicates an inverse relationship. As x goes up in value, c becomes smaller. To get c back in the numerator, the easiest way to do it is take the reciprocal of both sides.
What you get is c^1/3 = 1/x Now you can cube both sides.
c^(1/3)^3 = (1/x)^3 c^1 = 1^3 / x^3 c = 1 / x^3
D <<<<< answer. But that minus sign better be there.
To answer this specific question, <span>the all polar coordinates of point P are </span>(3, -π/4 + 2nπ) and [ -3, -π/4 <span>+ (2n + 1)π ]. </span>I am
hoping that this answer has satisfied your query about and it will be able to
help you, and if you’d like, feel free to ask another question.