Question

If p left parenthesis y right parenthesis equals startfraction 3 y minus 7 over y minus upper a endfractionp(y)= 3y−7 y−a and p left parenthesis 3 right parenthesisp(3)equals=negative 2−2​, what is the value of upper aa​?

Answer 1

$p(y)=\dfrac{3y-7}{y-A}\\\\p(3)=-2=\dfrac{3(3)-7}{3-A}=\dfrac{2}{3-A}\\\\3-A=\dfrac{2}{-2}\\\\3-(-1)=A=4$

The value of A is 4.