Question

A line passes through (6,3) , (8,4) and (n,-2) what is the value of n.

Answer 1

$\left[\begin{array}{ccc}6&3&1\\8&4&1\\n&-2&1\end{array}\right]=0$
$6*4*1+3*n*1+8*(-2)*1-1*4*n-6*(-2)*1-8*3*1=0$
$24+3n-16-4n+12-24=0$
$3n-4n+\diagup\!\!\!\!\!24-16+12-\diagup\!\!\!\!\!24=0$
$3n-4n-16+12=0$
$-n-4=0$
Keep the number on the left incognito and Put the number on the right without incognito by changing the sign.
$-n =4$ simplify by (-1)
$\boxed{n = - 4}$

Answer:
$\boxed{n = -4}$