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harina [27]
3 years ago
6

Classify the real numbers as rational or irrational numbers.

Mathematics
2 answers:
loris [4]3 years ago
7 0

Answer:

omg I'm working on this one too and I cant figure it out did you ever get the answer I can t find it anywhere and I'm not sure what it is all I have is 400 is rational

Step-by-step explanation:

krek1111 [17]3 years ago
6 0

Rational numbers

-5/250

\sqrt{400}

irrational numbers

5.01212121212....

\sqrt{1,000}

\sqrt[3]{30}

0.01562138411....

Step-by-step explanation:

sorry i answered late

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Juliette [100K]

Answer:

Minimum unit cost = 5,858

Step-by-step explanation:

Given the function : C(x)=x^2−520x+73458

To find the minimum unit cost :

Take the derivative of C(x) with respect to x

dC/dx = 2x - 520

Set = 0

2x - 520

2x = 520

x = 260

To minimize unit cost, 260 engines must be produced

Hence, minimum unit cost will be :

C(x)=x^2−520x+73458

Put x = 260

C(260) = 260^2−520(260) + 73458

= 5,858

7 0
3 years ago
What number needs to be subtracted from both sides of the equation 40 = 25 + x in order to solve for x? HELP PLEASE!!!
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Answer:

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3 years ago
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Solve the system of equations by graphing: 2x + 3y = 2 6x + 18y = 9
cluponka [151]
The answer is  A: x=1/2 , y= 1/3

Solve the following system:
{2 x + 3 y = 2 | (equation 1)
{6 x + 18 y = 9 | (equation 2)

Swap equation 1 with equation 2:
{6 x + 18 y = 9 | (equation 1)
{2 x + 3 y = 2 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:
{6 x + 18 y = 9 | (equation 1)
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Divide equation 1 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Multiply equation 2 by -1:
{2 x + 6 y = 3 | (equation 1)
{0 x+3 y = 1 | (equation 2)

Divide equation 2 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x+y = 1/3 | (equation 2)

Subtract 6 × (equation 2) from equation 1:
{2 x+0 y = 1 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 1/2 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Collect results:
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3 years ago
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natali 33 [55]
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3 years ago
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Nana76 [90]

Answer:

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Step-by-step explanation:

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