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3 years ago

Simplify 6/10X^2 divided by 6/10^3 -60^2

Mathematics

1 answer:

CaHeK987 [17]3 years ago

7 0

Answer: x - 6

Explanation:

$\cfrac{6}{10x^2} \div \cfrac{6}{10x^3 - 60x^2}$

$= \cfrac{6}{10x^2} \times \cfrac{10x^2(x - 6)}{6}$

$= x - 6$

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Answer:

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A statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20. Use thi

rjkz [21]

Answer:

\mu = 14.5\\

\sigma = 5.071\\

k = 1.084

Step-by-step explanation:

given that a statistician uses Chebyshev's Theorem to estimate that at least 15 % of a population lies between the values 9 and 20.

i.e. his findings with respect to probability are

$P(9$

Recall Chebyshev's inequality that

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Thus from the given information we find that

$\mu = 14.5\\\sigma = 5.071\\k = 1.084$

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3 years ago

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2 years ago

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Answer:

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Step-by-step explanation:

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