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denis-greek [22]

3 years ago

11

members of students council set up 96 chairs for a school meeting. they placed the chairs in rows,with an equal number of chairs

in each row.how many rows could they have set up? 5 equal rows,6 equal rows,10 equal rows,14 equal rows

1 answer:

Sauron [17]3 years ago

6 0

Answer:

6

Step-by-step explanation:

96÷5=19.2

<u>96÷6=16</u>

96÷10=9.6

96÷14=6.857142~

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John’s teacher gave him the following system of equations and asked him to find the point of intersection. 3x + 2 = y 2x – 3= y

Galina-37 [17]

1) to this case you must match both equations

3x+2 = 2x-3 ⇒3x-2x = -3-2⇒x= -5

now the value of x substitute it in the any of two equations, y = 3(-5)+2 = -13

and the other equation is the same value

y = 2(-5)-3 = -13

the point is ( -5,-13)

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Step-by-step explanation:

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2 years ago

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Blababa [14]

Answer:

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Step-by-step explanation:

4 0

3 years ago

6000 for 6 years at 81/2 % compounded daily will grow to a) $9.990.02 b)9.060.00 c) 9788.81 d)9991.15

Flura [38]

Answer:

d)9991.15

Step-by-step explanation:

We have a sum of money ($6000) compounded daily at an annual interest rate of 8.5% for 6 years.

If the interest is compound daily, and we take a m=365 days a year (or 365 subperiods m), the daily nominal interest rate is:

$i_d=\dfrac{i}{m}=\dfrac{0.085}{365}=0.000232877$

Then, we can express the final valueo of $6000 compounded daily at an annual interest rate of 8.5% for 6 years as:

$FV=IV\left(1+\dfrac{i}{m}\right)^{n\cdot m}\\\\\\FV=6000(1+0.000232877)^{6\cdot 365}\\\\FV=6000(1.000232877)^{2190}\\\\FV=6000\cdot1.665192322\\\\FV\approx9991.15$

4 0

3 years ago

What additional information could be used to prove ABC MQR using SAS?

Igoryamba

Answer:

To prove that ΔABC ≅ ΔMQR using SAS, we show that two sides with the intersection angle are congruent.

From the diagram, it is shown that CA is congruent to RM.

From the first option, given that m∠A = 64° and AB = MQ = 31 cm, then we have CA = RM, AB = MQ, and CAB = RMQ (i.e. m∠A = m∠M = 64°).

This shows that the first option is correct.

From the second option, given that CB = MQ = 29 cm, then we have CA = RM, CB = MQ, but ACB is not congruent to RMQ.

Thus the second option in not correct.

From the third option, m∠Q = 56° and CB ≅ RQ, then we have CA = RM, CB = RQ, ACB = 60°, but we do not know the value of MRQ.

Thus the third option is not correct.

From the fourth option, m∠R = 60° and AB ≅ MQ, then we have CA = RM, AB = MQ, RMQ = 64°, but we do not know the value of CAB.

Thus the fourth option is not correct.

From the fifth option, AB = QR = 31 cm, then we have CA = RM, AB = QR, but we do not know the value of CAB or MRQ.

Thus, the fifth option is not correct.

Therefore, the additional information that could be used to prove ΔABC ≅ ΔMQR using SAS is m∠A = 64° and AB = MQ = 31 cm

6 0

3 years ago