1. Joe- 2+b (or 2+1b)
Micheal- 2b
2. Joe- 2+10=12
Micheal- 2x10=20
3. one distributes and the other just adds regularly.
The question is asking for the lower bound of the 95% two tailed Confidence interval of the normally distributed population.
95% C.I. is given by 200 + or - 1.96(25) = 200 + or - 49 = (151, 249)
Therefore, the minimum weight of the middle 95% of players is 151 pounds.
Answer:
d)25 percent
Step-by-step explanation:
5/20×100
0.25×100
25 percent
Mark brianliest if my answer suit your question.
Answer:
1800
Step-by-step explanation:
24 divided by 4 equals 6. So 6 multiplied by 300 equals 1800.
