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musickatia [10]

3 years ago

11

2 algebra books and 3 geometry books cost $ 34, and 2 algebra and 2 geometry books cost $ 36. how much are each of the books

1 answer:

marishachu [46]3 years ago

5 0

There is an app called photo grid-photo Mass I meant sorry you should use it

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Lindsay says all numbers that are multiples of 4 have 2 as a factor. Is lindsay correct?

m_a_m_a [10]

Answer:

Yes

Step-by-step explanation:

Let's take any random multiple of 4 as an example:

8 = 2 • 4

64 = 2 • 32

20 = 2 • 10

Try any multiple of 4—this pattern continues.

7 0

3 years ago

A section of a rectangle is shaded. The area of the shaded section is 63 square units. What is the value of x?

ella [17]

Answer:

$x=11$

Step-by-step explanation:

We have been given a graph of a rectangle. The area of the shaded section is 63 square units. We are asked to find the value of x.

We can see from our given graph that shaded section forms a trapezoid, so we will use area of trapezoid formula to find the value of x.

$\text{Area of trapezoid}=\frac{(a+b)}{2}\times h$ , where, a and b represents the parallel sides of trapezoid and h represents height of trapezoid.

Upon substituting our given values in above formula we will get,

$63=\frac{7+x}{2}\times 7$

$63=(7+x)*3.5$

Upon dividing both sides of our equation by 3.5 we will get,

$\frac{63}{3.5}=\frac{(7+x)*3.5}{3.5}$

$18=7+x$

Let us subtract 7 from both sides of our equation.

$18-7=7-7+x$

$11=x$

Therefore, the value of x is 11 units.

5 0

3 years ago

Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

So

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

1 year ago

If you have 3 dollars and spend 1.50 how much do you have left

solong [7]

You have 1.50 left hope that helps

8 0

3 years ago

Read 2 more answers

Brainlist please help

Veronika [31]

8•4/1 = 32

Part A: Answer B
Part B: Answer A

8 0

3 years ago